1. If the cell voltage is 0.473 V what is the pH of the cathode compartment...
Part A Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.640 V when [Zn240.27 M and PH = 0.85 atm. Express your answer using two decimal places. V ΑΣφ pH =$ Figure 1 of 1 Previous Answers Request Answer Submit Switch 8.76 X Incorrect; Try Again; 2 attempts remaining Voltmeter Zn anode NO Na - H2(g) Cathode compartment (standard hydrogen electrode) NO3 Zn2 Provide Feedback Next Anode compartment NO3...
1. Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.610 V when [Zn2+]= 0.20 M and PH2= 0.92 atm . Express your answer using two decimal places. pH= Switch 8.76 Voltmeter 7n anode NO, Na +H (8) Cathode compartment (standard hydrogen electrode) Anode compartment NO, Zn2+ NO NO, Zn(s) —> Zn2+ (aq)+ 2e 2H+ (aq) + 2e →H(8)
this is the complete question (no more info) Determine the voltage (V) of the following cell at 25°C: Zn(s) | Zn2+(aq, 0.37 M) || Cl-laq, 0.75 M) C12(g, 0.750 atm)| Pt Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Hg2Cl2(s) + 2e --> 2Hg(l) + 2Cl(aq); E° = +0.27 V AgCl(s) + e --> Ag(s) + Cl (aq); E° = +0.22 V Ni2+(aq) + 2e --> Ni(s); E° =...
What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Agt concentration is 8.96x10-4 M and the Zn2+ concentration is 1.05 M ? 2Ag+(aq) + Zn(s)—>2Ag(s) + Zn2+(aq) Answer: V The cell reaction as written above is spontaneous for the concentrations given: __ What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cl2 pressure is 1.94x10-4 atm,...
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
In a test of a new reference electrode, a chemist constructs a voltaic cell consisting of a Zn/Zn2+ half-cell and an H2/H+ half-cell under the following conditions: [Zn2+ ] = 0.021 M [H+ ]= 1.3 M partial pressure of H2 = 0.32 atm. Calculate Ecell at 298 K (enter to 3 decimal places). Zn2+ (aq) + 2e − ⟶ Zn(s) E° = − 0.76 V 2H+ (aq) + 2e − ⟶ H2(g) E° = 0.00 V We were unable...
Consider a voltaic cell al 25 degree Celsius in which the reaction is: Zn (s) + 2H+ (aq) → Zn2+ (aq) + H2(g) It is found that the voltage (think Ecell) is +0.560 V when [Zn2+1 -0.85 M and PH2 = = 0.988 atm. What is the pH in the H2-H half-cell?
If the potential of a Zn-H+ cell (see below) is 0.45 V at 25 C when the [Zn2+] = 1.0M and PH2 = 1 atm, what is the pH of the cathode solution? Zn(s)|Zn2+(aq)|| H+(aq)|H2 (g)|Pt
Calculate the cell potential for the galvanic cell in which the given reaction occurs at 25 °C, given that [Zn²+] = 0.00100 M and (Au°+] = 0.863 M. Standard reduction potentials can be found in this table. 3 Zn(s) + 2 Aul+ (aq) = 3 Zn2+ (aq) + 2 Au(s) V EE 2.25 Incorrect
Reaction Eo Ag+(aq)+ e-→ Ag(s) 0.80V Zn2+(aq)+ 2e-→Zn(s) -0.76V What would be the cathode reactant in the Voltaic Cell made from the half-reactions above? Question options: a. Zn2+(aq) b. Ag+(aq) c. Ag(s) d. Zn(s)