Answer a:- Fraction derivative=
Sample |
1 |
2 |
3 |
4 |
Numbers with errors |
4 |
1 |
6 |
12 |
Fraction Derivatives |
4/23=0.17 |
1/23=0.0435 |
6/23=0.26 |
12/23=0.52 |
Answer b:- (17+4.35+26+52)/4=99.35/4=24.84%
Answer c:- Mean = 0.2484
Using samples of 200 credit card statements, an auditor found the following: Use Table-A. Sample Number...
Problem 4. Using samples of 200 credit card statements, an auditor found the following: Number with errors 4 25 9 a. Determine the fraction defective in each sample. b. If the true fraction defective for this process is unknown, what is your estimate of it? e. What is your estimate of the mean and standard deviation of the sampling distribution of fractions defective for samples of this size? d. What control limits would give an alpha risk of 03 for...
I need answers to E - H please. Table A Areas under the normal curve, 0 to z 01 Z 00 15 19 Use Table-A 3 4 2 Sample Number with errors 7 5 4 a. Determine the fraction defective in each sample. (Round your answers to 4 decimal p Fraction defectve Sample 0.0253 1 0.0202 2 0.0354 3 0.0404 4 b.lf the true fraction defective for this process is unknown, what is your estimate of it? (Ro the "%"...
Table A Areas under the normal curve, 0 to z 03 Z 00 0080 0120 01 0478 0517 15 16 19 o00 DI 02 E# e.What alpha risk would control limits of .0470 and .0136 provide? (Round your intermediate calculations to 4 decimal places. Round your "z" value to 2 decimal places and "alpha risk" value to 4 decimal places.) 1, alpha risk z= fUsing control limits of .0470 and .0136, is the process in control? ook Oyes rint Ono...
need help with E-H please Areas under the normal curve, O to z Table A 07 05 08 03 FA ES % & 2 コ 3a2コ 00 3a833 3333 22p Using samples of 198 credit card statements, an auditor found the following: Use Table-A Banple Number with errora 1 4 4 7 a. Determine the fraction defective in each sample. (Round your answers to 4 decimal places.) Sample Fraction defective 00251 2 002021 00354 b.lf the true fraction defective for...
PLEASE HELP Use the following to answer questions 20-25: A company makes plastic cups. Four samples of 15 cups were taken from an ongoing process to establish ap chart for control. The samples and the number of defectives in each are shown in the following table: Sample n Number of Defectives 1 15 2 2 15 o 3 15 3 15 5 Question 22 1 pts What is the standard deviation of the sampling distribution of sample proportion defective? Please...
A quality control manager at a manufacturing facility has taken four samples with four observations each of the diameter of a part. Samples of Part Diameter in Inches 1 2 3 4 5.8 5.7 6.2 6.2 5.7 6.1 6.0 5.9 6.3 5.8 6.3 6.2 6.2 5.8 5.9 6.3 (a) Compute the mean of each sample. (Round answers to 3 decimal places, e.g. 15.250.) Mean of sample 1 Mean of sample 2 Mean of sample 3 Mean of sample 4 (b)...
Using samples of 500credit card statements, an auditor found the following: Use Table-A. Sample 1 2 3 4 Number with errors 5 3 6 9 a. What is the 3 sigma control limit for this process
Using samples of 200 credit card statements, an auditor found the following: Sample 1 2 3 4 5 6 Number of errors 8 2 9 9 8 4 Determine the 3-sigma UPPER control limit using the data above.
Twenty samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 20 samples, a total of 130 items were found to be defective. (a) What is an estimate of the proportion defective when the process is in control? (Round your answer to four decimal places.) (b) What is the standard error of the proportion if samples of size 100 will be used for statistical process control? (Round your answer to four decimal...
> Use the following to answer questions 20-25: A company makes plastic cups. Four samples of 15 cups were taken from an ongoing process to establish a p chart for control. The samples and the number of defectives in each are shown in the following table: Sample Number of Defectives 1 15 2 2 15 0 3 15 3 4 15 5 What is the proportion defective for Sample 1? 0 0.667 O 0.133 O 0.200 O 0.167 O 0.333...