Homework Answers
The reaction that takes place is:
H2SO4 + 2 KOH ----> K2SO4 + 2H2O
from given reaction for neutralisation,
2*number of moles of H2SO4 = number of moles of KOH
2*M(H2SO4)*V(H2SO4) = M(KOH) * V(KOH)
2*0.250*11.1 = M*21.5
M = 0.258 M
Answer: 0.258 M
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