A. Titration of a 11.0 mL solution of KOH requires 12.0 mL of 0.0310 M H2SO4 solution. B. If 28.0 mL of a 0.200 N acid solution is needed to reach the end point in titration of 17.5 mL of a base solut...

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A. Titration of a 11.0 mL solution of KOH requires 12.0 mL of 0.0310 M H2SO4 solution. B. If 28.0 mL of a 0.200 N acid solution is needed to reach the end point in titration of 17.5 mL of a base solut...

A. Titration of a 11.0 mL solution of KOH requires 12.0 mL of 0.0310 M H2SO4 solution.

B. If 28.0 mL of a 0.200 N acid solution is needed to reach the end point in titration of 17.5 mL of a base solution, what is the normality of the base solution?

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Answer 1

Answer #1

A) 2KOH + H2SO4 --------------------> K2SO4 + 2H2O

M1 V1 / n1 = M2 V2 / n2

M1 x 11.0 / 1 = 0.0310 x 12.0 / 2

M1 = 0.0169 M

KOH is monobasic .so normality = molarity

molarity = normality = 0.0169 M

B)

normality of base = 28.0 x 0.200 / 17.5

= 0.320 M

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Answer 2

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A. Titration of a 11.0 mL solution of KOH requires 12.0 mL of 0.0310 M H2SO4 solution. B. If 28.0 mL of a 0.200 N acid solution is needed to reach the end point in titration of 17.5 mL of a base solut...

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