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An Ag-Cd electrochemical cell is written as Cd (s) CdCl2 (0.010 M) || AgCl (s) CI-...
A. Calculate the cell potential that would result in the following electrochemical cell at 25oC: ...
A. Calculate the cell potential that would result in the following electrochemical cell at 25oC: Pt | UO22+(0.10M),U4+(0.22M),H+(0.60M) || Ag+(0.034M) | Ag Line notation is anode || cathode Write Nernst equations for the anode and cathode separately. Then Ecell = Ecathode - E anode B. If the electrochemical cell Ag/AgCl || Zn2+(x M) | Zn(s) develops a potential of -1.039 volts at 25oC, what is the Zn2+ concentration in the solution? (Answer in decimal format) Ag/AgCl reference electrode has E=0.199...
An electrochemical cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that...
An electrochemical cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). What species are produced at the electrodes under standard conditions? E° = +0.80 V Agt(aq) + e- → Ag(s) Cu2+(aq) + 2 e- → Cu(s) E° = +0.34 V O Ag(s) is formed at the cathode, and Cu(s) is formed at the anode. Ag(s) is formed at the cathode, and Cu2+ (aq) is formed at the anode. Cu(S) is formed...
Consider the following electrochemical cell, with a KCl(aq) salt bridge: Mn(s) | MnCl2(aq) || CdCl2(aq) |...
Consider the following electrochemical cell, with a KCl(aq) salt bridge: Mn(s) | MnCl2(aq) || CdCl2(aq) | Cd(s). Identify the matching pairs below. (Use each answer exactly once.) Note that for metals, the metal refers to chemical properties and the electrode refers to physical properties, though they are the same substance. Question 8 options: 1234567 manganese ions 1234567 Cl- ions 1234567 Cd2+(aq) 1234567 Mn electrode 1234567 Mn metal 1234567 electrons 1234567 Cd electrode 1. reducing agent 2. oxidizing agent 3. transferred...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous for this cell. Oxidation- Reduction- b) Which metal is the anode and which is the cathode? anode cathode c) Calculate the emf (Ecell) for this cell. Eceu =
An electrochemical cell is expressed as Cu(s) | Cu^2+ (0.20 M) || I^- (0.10 M) |...
An electrochemical cell is expressed as Cu(s) | Cu^2+ (0.20 M) || I^- (0.10 M) | I_3^- (0.20 M) | Pt. I_3^- + 2e^- rightarrow 3I^-, E^0 = 0.535 V Cu^2+ + 2e^- rightarrow Cu(s) E^0 = 0.339 V Please answer the following questions: a. Write half-cell reactions at anode and at cathode. b. Write whole-cell reaction. c. Calculate the potential/voltage of the cell. d. Calculate equilibrium constant for this whole-cell reaction.
A voltaic cell that uses the reaction PdCl42−(aq)+Cd(s) → Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential...
A voltaic cell that uses the reaction PdCl42−(aq)+Cd(s) → Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential of +1.03 V A. Write the half-cell reaction at the cathode. B. Write the half-cell reaction at the anode
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + €...
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
Consider the following electrochemical cell at 298.15 K: Cd(s) | Cd(NO3)2 (aq, m = 0.200) ||...
Consider the following electrochemical cell at 298.15 K: Cd(s) | Cd(NO3)2 (aq, m = 0.200) || KCl (aq, m = 0.0150) | Ag(s) | AgCl(s) A) Write the overall reaction. B) Calculate the standard cell potential and ∆GR°. C) Calculate the cell potential and ∆GR assuming activity coefficients are 1.00. D) Calculate the cell potential and ∆GR using the Debye-Huckel limiting law for the mean ionic activity coefficients. E) Is the cell reaction spontaneous as written? F) How much electrochemical...
A standard galvanic cell is constructed in which a Cd2+ | Cd half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Cho...
A standard galvanic cell is constructed in which a Cd2+ | Cd half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Choose all that apply.) The anode reaction could be Fe -> Fe2+ + 2e-. The anode compartment could be Hg2+|Hg. The cathode reaction is Cd -> Cd2+ + 2e-. As the cell runs, anions will migrate from the Cd2+|Cd compartment to the other compartment. In the...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
An electrochemical cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). What species are produced at the electrodes under standard conditions? E° = +0.80 V Agt(aq) + e- → Ag(s) Cu2+(aq) + 2 e- → Cu(s) E° = +0.34 V O Ag(s) is formed at the cathode, and Cu(s) is formed at the anode. Ag(s) is formed at the cathode, and Cu2+ (aq) is formed at the anode. Cu(S) is formed...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous for this cell. Oxidation- Reduction- b) Which metal is the anode and which is the cathode? anode cathode c) Calculate the emf (Ecell) for this cell. Eceu =
An electrochemical cell is expressed as Cu(s) | Cu^2+ (0.20 M) || I^- (0.10 M) | I_3^- (0.20 M) | Pt. I_3^- + 2e^- rightarrow 3I^-, E^0 = 0.535 V Cu^2+ + 2e^- rightarrow Cu(s) E^0 = 0.339 V Please answer the following questions: a. Write half-cell reactions at anode and at cathode. b. Write whole-cell reaction. c. Calculate the potential/voltage of the cell. d. Calculate equilibrium constant for this whole-cell reaction.
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
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