Question

In python Create a function that will take in an argument ( a 2D list of strings). The function will return a dictionary where the key is the first element of each row, and the key is the remaining elements. Example listOne ['aa', 'bb', 'cc', 'dd' ], ['ee', ff, 'gg', 'hh', 'ii', 'j' l ['kk', 'll', 'mm', 'nn' ] = Should return {'aa' : [ 'bb', 'cc', 'dd' ], 'ee' ff, 'gg', 'hh', 'ii, j' ] 'kk' : [ '', 'mm', 'nn' ] }

Answer 1

1 def main(): listone-[] #list create matrix (listone) #create matrix function 2 print("listone ",end-'') #printing listone for i in listOne: #iterates through each list in listone 5 6 print(i,",", sep='',end-'\n\t' ) #printing list 7 dic- #dictiona n (listOne)): #iterates loop from . length of each row ge (0,1 a=[ for j in range (1, len (list0ne [i ] ) ): #iterates length of column times for i in 11 12 a.append(listone [i] [j ]) #adds the elements to list except first element 13 dic[listone[i] [0] ]=a #creates dictionary element 14 15 F dC: #itecates through each key in dictionary 17 print(i,":",dic [i] , sep= ' ' ) 18 19 20 21 def create matrix(listone ) : print("Enter elements (-1 to enter next row and C ele-input() to exit the loop)") 24 while(ele!'0'): #if element is 0 stop the loop 25 a-[] while(ele!=' -1' ) : # if element is -1 then go to next row 26 27 a.append (ele ) t() 28 listone.a ele-input () 30 31 32 33 main

def main():
   listOne=[] #list
   create_matrix(listOne) #create matrix function
  
   print("listOne= ",end='') #printing listOne
   for i in listOne: #iterates through each list in listOne
       print(i,",",sep='',end='\n\t') #printing list
  
   dic={} #dictionary
   for i in range(0,len(listOne)): #iterates loop from 0 , length of each row
       a=[]
       for j in range(1,len(listOne[i])): #iterates length of column times
           a.append(listOne[i][j]) #adds the elements to list except first element
       dic[listOne[i][0]]=a #creates dictionary element
  
   print("\nDictionary: ")
   for i in dic: #iterates through each key in dictionary
       print(i,":",dic[i],sep='')
  

def create_matrix(listOne):
   print("Enter elements (-1 to enter next row and 0 to exit the loop)")
   ele=input()
  
   while(ele!='0'): #if element is 0 stop the loop
       a=[]
       while(ele!='-1'): #if element is -1 then go to next row
           a.append(ele)
           ele=input()
       listOne.append(a)
       ele=input()

main()

jack@jack-TravelMate-P243-M:~$ python3 dict.py Enter elements (-1 to enter next row and 0 to exit the loop) aa bb CC dd -1 ee ff gg hh ii jj -1 kk - 1 listone= ['aa', 'bb', 'cc', 'dd'], ['ee', 'ff', 'gg', 'hh', 'ii', 'jj'], ['kk', 'll', ' mm' , ' חה , Dictionary: aa:[ 'bb', 'cc', 'dd'] ee:['ff', 'gg', 'hh', kk:['ll', mm jack@jack-TravelMate-P243-M:~$ 'ii', 'jj'] 'חח' ]