From thermodynamic tables, Saturation pressure at 20 deg C is pg1 = 0.02339 bar
Therefore, pv1 =
1 pg1 where
denotes relative humidity
pv1 = 0.5 * 0.02339 = 0.011695 bar
Both the composition of the moist air and the mixture pressure remain constant, so the partial pressure of the water vapor at the exit equals the partial pressure of the water vapor at the inlet: pv2 = pv1 = 0.011695 bar.
From thermodynamic tables, at 30 deg C, we get saturation pressure pg2 = 0.04246 bar
Relative humidity at final state
2 = pv2 / pg2
= 0.011695 / 0.04246
= 0.27 or 27%
Please Help.! Having a hard time trying to figure this problem out.!! The answer is 27%.!!...
Please help.!! Having a hard time with this problem.!! Answer
for 10. Is) 0.0004 and 11. Is) 1.0.!! Thanks
In a desertme combiiation of a air conditioner (AC) nd an adiabatic humidier is employed to achieve desired level of temperature (ad ltive huity There isno condensationte AC Air enters the AC unit at 10 Pa, 4and 10% rmidity. Air leaves the adiabatic humidifier t 100, kPa, 25°C and 50% relative humidity Refrigerant Liquid water P, 100 kPa T, 45 C...
please provide me with the solutions as fast as possible
A gas mixture with id entical mass fractions for each component will have the identical mole fractions 1. T F as well. T F 2. The sum of the mass fractions for a real-gas mixture is equal to 1 The molar mass of Methane is 0.5182 kg/kmol. 3. A real-gas mixture has a compressibility factor of 0.49. Using the ideal gas relationship, 4. the volume of the mixture b. Underestimates...
I’m having a hard time trying to figure out the
rearrangements for the 2 reactions listed above. I only got 1/6 for
the second reaction.
CH3에 Podcts
Using the Compound Interest Tables answer these please. Having
really hard time figuring these out.
Problem 4: For the diagrams ad below, compute the unknown values W,X,Y,Z respectively, 25 : 50 75 - 100 10% 100 200 300 i = 10% 300 200 100 i = 10%
PLEASE HELP WITH THESE TWO, I AM HAVING HARD TIME WITH MATERIAL
IM TRYING TO ESTABLISH A PATTERN OR CONSISTENCY .THANK YOU
Implement Y-A+C B+D) using CMOS circuit Implement Y Y-A-B-C+A-B-C using CMOS circuit
Please help with solving these problems I am having a hard time trying to work them out 1. You need to make a 15% solution using 25 ml of a 80 % stock solution. How much sterile saline do you need to add to make this product? Round your answer to one decimal place (tenths), where appropriate. 2. Your are given 25 ml of a 80% solution and told to add (not dilute to) 275 ml. What will the final...
I am trying to figure out the mass flow rate of air required to
dry 310 kg of water from the product.
Wet product Mass = 400kg Water Mass = 320kg. Temprature = SOC Solid mass = Boky. M=? Humidity Ratio: 0.017kg DRIER Rhz ? Relative hum: 5.7% Enth 22 Euthlapy = 10.7285 Mass = 90 kg Specific Volume water mass= lokg. Speglie Volume = 102m3 Solid mass 2 Soka ng V DRY Product Water Removal rate : 44.26 kq
I know the answer to "A" is "1". However, I'm having a hard
time learning how to figure that out by working through the
problem. Please help me learn how to figure out the answer by
working through the problem.
A) Suppose the production function is q = 12-Ë·K'. Determine the long-run capital-to-labor ratio (K/L) if the cost of a unit of capital (r) is three times the cost of a unit of labor (1).
A) Suppose the production function...
im having a hard time with number 3 but if you can help me chall
all of them thst would be greatly appreciated
If the air pressure is 733 tor, what is the pressure in atm? 1 2 What wou ld be the pressure of 156 ml of gas at 695 tom after changing the volume to 256 ml? Consider the reaction: 3. KCIO3(s) KCI(aq) + O2(g) What would be the mass of KCIO, (s) needed to produce 2.0L of...
I need help trying to figure out how to solve for the bottom half of my table. Please show work so I can learn. Thanks! Data Table 1: Analysis of Alka-Seltzer Trial 1 Trial 2 Mass of acetic acid 4.97 g Density of acetic acid 1.00 g/mL 1.00 g/mL Concentration of acetic acid 0.88 M 0.88 M Mass of Alka-Seltzer 3.21 g 3.24 g Volume of NaOH, initial 0 mL 5.0 mL Volume of NaOH, final 0 mL 4.4 mL...