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Question 4 5 pts The truss structure is shown below. The horizontal concentrated load acting on node 2. Qx, is 21kN and the v

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DI 2 + 《一 8 4 gy=49kn 3 7 2 (0,3) Dx= 211N (4,3) y 3m 2 0 1 r (to x J 3 (0,0) (4,0) am AE = constant * Member:- 0-4 → cos (C)I KN 0.328 0.096 x =21 DI 9,=Gx 92 - Gy=496N = AE [ 0.096 0.405 D2 21.42 [:] I AE 114.73 * Internal force in Element ②: 8=TAF23 Г-. 19 (<N С +32 (п. 19 92F= (т. 14 км (Теміом) X (т. 14 («р 2 (Теміри) / (т. 19 (с NI hope I could help u dear

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