Question

Question 11 If the fragments shown in Table 1 are subjected to electrophoresis at a pH of 4, irn which direction will fragment 5 move? Towards the cathode B Toward the anode It will not move The direction of migration cannot be determined without more information Explanation From Table 1, the isoelectric point of fragment 5 is 9.74. At a pH below 9.74, the molecule will be protonated and hence positively charged. Since fragment 5 is in a buffer at pH 4 it will be positively charged and so will migrate to the negatively charged electrode; namely the cathode. This makes (A) the correct response.

I am confused on this question, the correct answer is A and I chose B. I thought the cathode was positively charged, and the anode was negateively charged; and a high PI would incicate a more positive charge, and a low PI would incidate a more negative chare. Are these correct or am I backwards in some these? Also, are any of these different for a galvanic or electrolytic cell?

Please explain how you would answer this question, thank you!

Answer 1

as auion ふ"Jw.e.t-S Catier