Question

The random sample shown below was selected from a normal distribution. 7, 6, 7, 3, 10,3 Complete parts a and b. a. Construct a 99% confidence interval for the population mean ?. (Round to two decimal places as needed.)

Answer 1

Confidence Interval Formula for u is as follows x = sample m ean, s sample standard deviation, tscore-statistic with (n-1) Degrees of Freedom and a-1-confidence Percentage Degrees of Freedom n-1 Degrees of Freedom -6-1 Degrees of Freedom 5 Calculate α: a-1-Confidence% a=1-0.99 a 0.01 Find a spread range a 0.005 Find t-score for ao.005 using 5 degrees of freedom: tscoreo.005 4.0321Valean be found on Excel using TINV(0.01,5) tscore 4.0321

SEM 2.4494 SEM 2.4494 2.4494897427832 SEM 1 Calculate high end confiden High End X tscore sn High End 64.0321 x 2.4494/6 High End 6+ 4.0321 x 0.99996336266219 High End 6+4.0319522745902 High End 10.03 fidenc Low End X - tscore * s/Nn Low End 6-4.0321 x 2.4494/6 Low End 6-4.0321 x 0.99996336266219 Low End 6-4.0319522745902 Low End = 1.97 Now we have everything, display our 99% confidence interval: 1.97 μ 10.03