pH formula is
pH = -log[H+]
Here concentration given is in molarity
Therefore pH of 0.85 M solution of No2- is
pH= -log [0.85]
pH = 0.070
What is the pH of 0.15 M aqueous nitrite ion? (Kb of NO2– = 1.7
× 10–11) NO2–(aq) + H2O(l) HNO2(aq) + OH-(aq)
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2. (10 pts) What is the pH of 0.15 M aqueous nitrite ion? (Kh of NO2 = 1.7 x 10"") NO2 (aq) + H2O(1) = HNO2(aq) + OH(aq)
What is the pH of a 0.180 M aqueous solution of potassium nitrite, KNO2? pH This solution is Submit Answer Retry Entire Group 9 more group attempts remaining
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