Question

Q1. Ideal diode and ideality factor Two solar cells have an open circuit voltage of 0.85 V and the same short circuit current under a given spectrum. One has an ideality factor of 1 the other has an ideality factor of 2. Use the diode equation to work out the dark saturation current in each case as a fraction of Jsc(You may neglect parasitic resistances). By finding the maximum of the power-voltage characteristic in each case compare the fill factors. How much more efficient is the 'ideal' diode as a photoconverter?

Answer 1

ANSWER :- waith Di ode equation, 1 = ls (eo/mvn)-1) where I is diode current Is is neverse Saturation cunent no is the diode voltage n is the ideality factor Vy is the thermal voltage In this equation S taking Vy = 1 and I = 1, since Considering both the quantities to be therefore, for ideality factor 1 1 » Is (€9.85/242-2) 1 - Is (e -1) 1 = Is (2.339 - 1) 1 - Is (1. 339) Is = 1/2,339 -10,74 682 amp] for ideality 2, I - Is ce 0.85/2-1) 1 - Is ce®-425 -4) 1 - Is (1, 529 -1) 1 - Is (0.529) Is a h sau [Is = 1.9011 ame] 3 0.52a Is = loqollamp