Question

I need the step by step solution on how to solve this problem. I need the answer Asap. your help is greatly appreciated. thank you. Problem 5

5. There are 10 different apples and 15 different pears. How many ways are there for Jack to pick an apple or a pear and then for Jill to pick an apple and a pear? A. 2735 B. 3450 C. 2275 D. 3060 total no. of ways = 8*7*6*5 = 1680 New! FREE algebra solver that shows work: 3x-X+2=4 Solve middle school mont OL a

Answer 1

solution ଏ ତ an OR Case We have 15 different apples and 10 different pears. Now Jack can choose Apple pear. Jack chooses an apple from the 15 different apples. So Jill can choose to apple from the remaining 14 different apples and one different pears. (5) (4) () 0mg, peare from the lo di So total number of choices this cases for this 2 Y5 x 14 x 10 = 2100 Case I Jack chooses a pear from the 10 different pears so Jill has to choose one pear from remaining a pears and one apple from the is apples of choices for this case (19)(3)(15)=1350 Hence total number of possible choices=13450 (Option B) so, NO.

Thus total number of possible choices is 2100+1350 = 3450.

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