M(OH)2 ---> M+2 + 2OH-
From the stoichiometry of the above eqaution we find that for every mol of M, 2 mols of OH is consumed. Therefore, to find the Ksp,
Ksp=[M2+][OH-]. Instead of using the [M2+], we can substitute in [OH-/2],
First pH = 10.16
So pOH =14-10.16=3.84
pOH=3.84
pOH = 3.84
[OH-] = 10^-3.84
[OH-] = 1.45*10^-4M
[M+2] = 1.45*10^-4M/2=7.25*10^-5M
ksp= [M+2]*[OH-]^2
= [7.25*10^-5]*[ 1.45*10^-4]^2
=1.52*10^-12
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