Question

Solve the two equations mvi + MVi = mvf + MVf and vi − Vi =...

Solve the two equations mvi + MVi = mvf + MVf and vi − Vi = −(vf − Vf) for vf and Vf if m = 1.90 kg, vi = 4.05 m/s, M = 3.10 kg, and Vi = 0.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

mvi + MVi = mvf + MVf

1.90 ( 4.05) + 3.10( 0) = 1.90 (vf) + 3.10( Vf)

7.695 = 1.90 (vf) + 3.10( Vf)---------eq(1)

vi − Vi = −(vf − Vf)

4.05 = - vf+ Vf---------eq(2)

vf= Vf- 4.05 ( plugging this value in eq(1)

7.695 = 1.90 (Vf- 4.05) + 3.10( Vf)

7.695 = Vf( 1.90 + 3.10) - 7.695

15.39 = Vf( 5)

Vf= 3.078 m/s

vf= Vf- 4.05 = 3.078 - 4.05= -0.81 m/s

Add a comment
Know the answer?
Add Answer to:
Solve the two equations mvi + MVi = mvf + MVf and vi − Vi =...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Calculate Average Force for a tennis ball if m=0.057 kg, vi = -30 m/s, vf =...

    Calculate Average Force for a tennis ball if m=0.057 kg, vi = -30 m/s, vf = 58 m/s, and t = 5 ms = 5 x 10-3 s mass of the ball = 0.057 kg Initial velocity = vi = - 30 m/s Final velocity = vf = 58 m/s time of contact t = 5x10-3 s FORCE ?

  • A block with mass M = 5.95 kg is sliding in the positive x-direction at Vi...

    A block with mass M = 5.95 kg is sliding in the positive x-direction at Vi = 8.90 m/s on a frictionless surface when it collides elastically in one dimension with a stationary block with mass m = 1.30 kg. Determine the velocities, Vf and vf, of the objects after the collision.

  • A speedboat increases its speed uniformly from vi = 20.0 m/s to vf = 29.0 m/s...

    A speedboat increases its speed uniformly from vi = 20.0 m/s to vf = 29.0 m/s in a distance of Δx = 1.60 ✕ 102 m. (a) Draw a coordinate system for this situation and label the relevant quantities, including vectors. A speedboat in two positions is shown. The speedboat on the left has a speed vi with its vector pointing to the right. The speedboat on the right is at a distance of Δx (in meters) from the speedboat...

  • Added load m1(g) Added load m2(g) vi,1(m/s) vi,2(m/s) vf(m/s) measured vf(m/s) calculated Error % Vf,m- Vf,c...

    Added load m1(g) Added load m2(g) vi,1(m/s) vi,2(m/s) vf(m/s) measured vf(m/s) calculated Error % Vf,m- Vf,c Vf,c×100 0 0 0.462 0 0.245 0.231 6% 100 0 0.564 0 0.327 0.282 15% 140 40 0.478 0 0.268 0.239 12% 140 100 0.399 0 0.175 0.199 12% 100 140 0.273 0 0.134 0.136 1.74% 40 140 0.4502 0 0.201 0.225 10.6% 0 100 0.526 0 0.125 0.263 18.2% a. Which effect has increasing of mass on initial and final velocity of the...

  • One of the most popular kinematic equations is the one for final velocity: vf = vi...

    One of the most popular kinematic equations is the one for final velocity: vf = vi + a*t, where vf = final velocity, vi = initial velocity, a = acceleration and t = time. Write a method that calculates this formula given the arguments. Then in your main, ask the user to input the initial velocity and acceleration for 2 items. Finally, output their increasing velocities over 10 timesteps, calling your method in each iteration. Example Output: Enter the initial...

  • A block of mass m=7.6kg, moving on a frictionless surface with speed vi= 7.6m/s, makes a...

    A block of mass m=7.6kg, moving on a frictionless surface with speed vi= 7.6m/s, makes a perfectly elastic collision witha block of mass M at rest. After the collision, the 7.6 kg block recoils with a speed of vf=2.5m/s. In the figure, the blocks are in contact for 0.20 s. The average force on the 7.6 kg block, while the two blocks are in contact, is the closest to: 241N, 194N, 289N, 336N, 384N

  • Name: SHOW ALL WORK FOR PROPER CREDIT!! 1. Given the simultaneous equations in terms of Vi...

    Name: SHOW ALL WORK FOR PROPER CREDIT!! 1. Given the simultaneous equations in terms of Vi and V2. Perform the necessary algebraic manipulation to put the two equations in a matrix form and then solve for V1 and V2. (10 points) V1 - 12 +2+1 + V1 - V2 = 0 V2 - v1 + 2 - 4 = 0 V-12

  • During a rain storm, rain comes straight down with a velocity Vi = -15 m/s and...

    During a rain storm, rain comes straight down with a velocity Vi = -15 m/s and hits the roof of a car perpendicularly. The mass of the rain per second that strikes the roof is 0.060 kg every second. Assuming that the rain comes to rest upon striking the car (Vf = 0 m/s), find the average force exerted by the rain on the roof during a 3 second time interval.

  • Use the worked example above to help you solve this problem. In a crash test, a...

    Use the worked example above to help you solve this problem. In a crash test, a car of mass 1.44 103 kg collides with a wall and rebounds as shown in the figure. The initial and final velocities of the car are vi = -15.2 m/s and vf = 2.11 m/s, respectively. If the collision lasts for 0.153 s, find the following. (a) the impulse delivered to the car due to the collision kg · m/s (b) the size of...

  • Someone throws a ball upward with an initial velocity of vi. Use the free fall equations...

    Someone throws a ball upward with an initial velocity of vi. Use the free fall equations to determine and show the final velocity vf the ball has when it returns to the height from which it was released (hint you want a final equation that contains those two variables and no others). (further hint: what hidden information can you get from the phrase “returns to the height from which it was released”?) Ignore air resistance

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT