Consider a population of 100 individuals and the frequency of the A allele is 0.6 and the frequency of the a allele is 0.4. If the following fitness values for each genotype are applied to the next generation, what will be the frequency of the A allele in the next generation?
wAA = 1
wAa = 0.25
waa = 0.25
Answer Choices:
a. .81
b. .64
c. .92
d. .73
e. .54
The answer will be 0.81 (Option a).
Explanation: Given, frequency of A = 0.6, frequency of a = 0.4, wAA = 1, wAa = 0.25, waa = 0.25
So, frequency of AA = (frequency of A)2 = (0.6)2 = 0.36
So, frequency of aa = (frequency of a)2 = (0.4)2 = 0.16
So, frequency of Aa = 2 x frequency of A x frequency of a = 2 x 0.6 x 0.4 = 0.48
Now, mean relative fitness = (Frequency of AA x Fitness of AA) + (Frequency of Aa x Fitness of Aa) + (Frequency of aa x Fitness of aa) = (0.36 x 1) + (0.48 x 0.25) + (0.16 x 0.25) = 0.36 + 0.12 + 0.04 = 0.52
Now, after selection frequency of AA = (Frequency of AA x Fitness of AA) / mean relative fitness = (0.36 x 1) / 0.52 = 0.692 (Up to 3 decimal)
Now, after selection frequency of Aa = (Frequency of Aa x Fitness of Aa) / mean fitness = (0.48 x 0.25) / 0.52 = 0.231 (Up to 3 decimal)
So, frequency of A allele in the next generation = Frequency of AA + 1/2 of Frequency of Aa = 0.692 + (0.5 x 0.231) = 0.80755 = 0.81 (Up to 2 decimal)
Consider a population of 100 individuals and the frequency of the A allele is 0.6 and...
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