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![Ni (Br O3)2 = 58.6934 +(79.904 + 3x 15.9994]*2 So molar mass Ni (2003), = 314.4978.hel? ç mass = molar mass x moles mass of N](http://img.homeworklib.com/questions/c594ba80-5922-11eb-a41b-09f6afe2a931.png?x-oss-process=image/resize,w_560)
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4. A 100.0 mL solution of nickel (II) bromate, Ni(BrO3)2, IS 0.1010 mol/L. a. How many...
A 10.00 mL sample of an unknown aqueous nickel(II) solution (density = 1.00 to produce 0.0532...
A 10.00 mL sample of an unknown aqueous nickel(II) solution (density = 1.00 to produce 0.0532 g of Ni(DMG)2 (Molar Mass=288.9155g/mol) precipitate. aqueous nickel(II) solution (density = 1.00 g/mL) was treated and found of nickel in the unknown solution. olar Mass - 288.9755e/molnrecinitate. Calculate the mass percentage
1. how many moles of HCI are in 100.0 mL of a 0.05M HCI solution? 2....
1. how many moles of HCI are in 100.0 mL of a 0.05M HCI solution? 2. What is the molarity of a solution formed when 5.25g of NaOH is dissolved in 63mL of water?
What is the molarity of Na when 100.0 mol of Na2SO4 is dissolved in 20.00 L...
What is the molarity of Na when 100.0 mol of Na2SO4 is dissolved in 20.00 L of water. (Assume the volume of solution equals the volume of water.) What is the molarity of SO42- when 100.0 mol of Na2SO4 is dissolved in 20.00L of water. (Assume the volume of solution equals the volume of water.) How many moles of sulfuric acid are in 300.0 mL of 2.00 M H2SO4(aq) What volume (in mL) of 5.00 M HCl(aq) contains 10.0 mol...
Calculate molarity of 10.00 g/L solution of the salt, if its molar mass is 100.0 g/mol...
Calculate molarity of 10.00 g/L solution of the salt, if its molar mass is 100.0 g/mol and solution density D=1.100 g/mL.
A 3.82 L volume of gaseous ammonia, NH3 (g), at STP is bubbled through 100.0 mL...
A 3.82 L volume of gaseous ammonia, NH3 (g), at STP is bubbled through 100.0 mL water and reacts completely to form ammonium hydroxide, NH4OH (aq). a) What is the molar concentration of the resulting NH4OH (aq) solution? b) What mass of NH4OH is present in the 100.0 mL solution? c) How many moles of NH4OH would be present in 482 mL of a solution of the same concentration?
please answer all please Test No 73 M NasPO42 N 2.(8) a. How many moles of...
please answer all please
Test No 73 M NasPO42 N 2.(8) a. How many moles of Na b. What is the molarity of Na'? NAME: POs are the 0250 L solution of 0.873 M 3. (7) What is the molarity of a NaOH solution th solution? (NaOH Molar Mass: 40.00 g/mol). In that contains 4.27 g of NaOH in 125.0 mL of 4. (8) Na2SO4 + a) Balance the above reaction. b) If 63.8 mol of Na2SO4 is used, how...
The concentration of NaH2PO4 in a solution is 3.23 x 10-4 mol/L.
The concentration of NaH2PO4 in a solution is 3.23 x 10-4 mol/L. (a) Find the molarity (in mol/L) of Pin the solution. (b) What is the concentration of P in ppm or mg/L (molar mass of P = 30.97). (c) If 5.00 mL of the above solution was transferred into a 1.00-Liter volumetric flask and then dilute to the mark with DI water, what is the concentration of P in ppm after dilution?
date ory Assignment (d) How many moles of barium sulfate were ac- tually formed? mol answer...
date ory Assignment (d) How many moles of barium sulfate were ac- tually formed? mol answer (a) What was the percent yield of barium sulfate? (d) How many mo tually formed? 1. Read in an appropriate reference a discussion of precipitation, filtration, and drying of precipitates and of mass measurements. 2. Barium sulfate, Baso was prepared by reacting 100.0 mL of 0.0500M potassium sulfate solution with 100.0 mL of 0.0700M barium nitrate solution, follow- ing the procedure of this experiment....
Trial 1 Acetic acid / L solution 2.402g/L Volume of acetic acid (mL) 30 mL Initial...
Trial 1 Acetic acid / L solution 2.402g/L Volume of acetic acid (mL) 30 mL Initial buret volume (mL) 0.2 mL Final buret volume at end point (mL) 18.2 mL Total volume of NaOH titrated (mol) 18.0 mL Moles of NaOH titrated (mol) Molarity of acetic acid (mol/L) Molar mass of acetic acid Average volume of NaOH titrated mL Average molar concentration of acid Average molar mass of acetic acid
How many grams of AgNO3 are required to make 770.0 mL of a 0.15 M solution?...
How
many grams of AgNO3 are required to make 770.0 mL of a 0.15 M
solution?
How many grams of AgNO3 are required to make 770.0 mL of a 0.15 M solution? The molar mass of silver nitrate is 169.9 g/mol. One approach is to solve the molarity relationship (M- n/N) for moles. o a 19.6g b. 6.82 g O5.10 g o d. 1.95 g O e. None of the above
A 10.00 mL sample of an unknown aqueous nickel(II) solution (density = 1.00 to produce 0.0532 g of Ni(DMG)2 (Molar Mass=288.9155g/mol) precipitate. aqueous nickel(II) solution (density = 1.00 g/mL) was treated and found of nickel in the unknown solution. olar Mass - 288.9755e/molnrecinitate. Calculate the mass percentage
What is the molarity of Na when 100.0 mol of Na2SO4 is dissolved in 20.00 L of water. (Assume the volume of solution equals the volume of water.) What is the molarity of SO42- when 100.0 mol of Na2SO4 is dissolved in 20.00L of water. (Assume the volume of solution equals the volume of water.) How many moles of sulfuric acid are in 300.0 mL of 2.00 M H2SO4(aq) What volume (in mL) of 5.00 M HCl(aq) contains 10.0 mol...
please answer all please
Test No 73 M NasPO42 N 2.(8) a. How many moles of Na b. What is the molarity of Na'? NAME: POs are the 0250 L solution of 0.873 M 3. (7) What is the molarity of a NaOH solution th solution? (NaOH Molar Mass: 40.00 g/mol). In that contains 4.27 g of NaOH in 125.0 mL of 4. (8) Na2SO4 + a) Balance the above reaction. b) If 63.8 mol of Na2SO4 is used, how...
date ory Assignment (d) How many moles of barium sulfate were ac- tually formed? mol answer (a) What was the percent yield of barium sulfate? (d) How many mo tually formed? 1. Read in an appropriate reference a discussion of precipitation, filtration, and drying of precipitates and of mass measurements. 2. Barium sulfate, Baso was prepared by reacting 100.0 mL of 0.0500M potassium sulfate solution with 100.0 mL of 0.0700M barium nitrate solution, follow- ing the procedure of this experiment....
How
many grams of AgNO3 are required to make 770.0 mL of a 0.15 M
solution?
How many grams of AgNO3 are required to make 770.0 mL of a 0.15 M solution? The molar mass of silver nitrate is 169.9 g/mol. One approach is to solve the molarity relationship (M- n/N) for moles. o a 19.6g b. 6.82 g O5.10 g o d. 1.95 g O e. None of the above
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