Question

Please Help

assighmentProblemiD-49834820 colege physics i HWCHOS Problem 6.11 previous 4 of 14 Problem 6.11 Part A To move a large crate ac ross a rough floor, you push on it with a force F at an angle of 21 below the horizontal as shown in the figure.Figurc1 Find the acceleration of the crate if the applied force is 350 N, the mass of the crate is 32 kg and the coefficiont of kinetic fnchion is 0.40 Express your answer using two signifilcant figures. m/굼 Submit My Answers Grre Up Incorrect, Try Again; 6 attempts remaining Continue

Answer 1

The free body diagram is given as follows, Ft Fi sin21 F. Fi Cok 21 W: m

From the free body diagram it is clear that, Fy is the normal force acting on the body Normal force = Weight of the given body F, is the frictional force acting on thebody Force F has two components, F cos 21° and Fsin 21°. F sin 21 is the vertical force. It has no role in the movement of the crate. Only the horizontal forces are responsible for the movement of the crate So the net force acting on the crate is, F-F cos 21°-F = F1 cos 21°-uk mg = 350x 0.93-0.40x 32x9.8 200.06 N

F ma dr a- 1n 200.06 32 a- 6.25 Therefore the acceleration of the crate was found to be6.25