Question

10) The wires in the circuit shown in the diagram are made of the same material, but one segment of the wire is thinner than the other wires. Copy the diagram a) On your copy of the diagram, at the x locations labeled B and C, draw arrows representing the electric fields at those locations. The arrows should point in the correct direction and be drawn to represent relative strengths, with longer arrows representing larger fields. b) At the x locations labeled 1, 2, and 3, sketch out a distribution of surface charges consistent with this scenario. 2 X B

Answer 1

of length el and a ) area क Be gs resistincity resistance of conductor cross section 'A' is R = 8 A AV- potential difference ence across it's ends AV - IR as El= Isl AV = El π A T £ I s А. area न cross section of B = AB is less than area of cross section of c= Ac А. 2 А. Housever current through B and C is same as current is series remains constant » Is = Ic ie Electric field is inversely proportional to area of ² Ex) A cross section so Eg> b ) tttt + CJĘ tt + B + + EB locations is closer to positive terminal so it has greater concentration of positive change on everface as compared to 2 and 3.

please rate it up thanks :)