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If 0.2 grams mono carboxylic acid x (having one COOH group) are dissolved in 20 mL...
ABCDE ABCDE AaBbCcD ABCDE AaBb AEDEL -X, X ADA ! Normal No Spacing Heading 2 9)...
ABCDE ABCDE AaBbCcD ABCDE AaBb AEDEL -X, X ADA ! Normal No Spacing Heading 2 9) A student was given 0.2 g of an unknown carboxylic acid to determine its molecular weight. He/She first dissolved it into 95% ethanol, added 3 drops of phenolphthalein indicator then titrated it with standardized 0.IN NaOH solution. 15 ml NaOH was needed to reach the neutralization point. Please, answer following questions. (10 pts) a. Write down the general acid-base neutralization reaction? b. What is...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.773 Volume of NaOH required to reach endpoint: (ml) 19.0 pH of the mixture Ihalf neutralized solution 3.54 Calculate the following...
Data i got: 1g of solid acid=0.51706 ml 50 ml of water used to dissolve 0.5...
Data i got:
1g of solid acid=0.51706 ml
50 ml of water used to dissolve
0.5 ml of indicator added to acid solution
8.52 ml of 1M NaOH titrated from burrete into acid
solution.
The virtual lab stockroom contains NaOH, water and an unknown solid weak acid. Perform experiments to identify the pka and molar mass of the bottle of unknown solid acid. You may enter your answer in the form below the Virtual Lab NOTE: You can submit your...
A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and...
A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NAOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H806 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 14.47 Concentration of NaOH in mol/L, 0.1964 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg). Answer:
3. 0.7253 g sample containing an unknown weak acid HA was dissolved in 50 mL water...
3. 0.7253 g sample containing an unknown weak acid HA was dissolved in 50 mL water and titrated against 0.1555 M NaOH, requiring 48.11 mL to of NaOH to reach the end-point. During the titration reaction, the pH of the solution is 3.77 when half of the HA is neutralized and the equivalence-point pH is 8.33. (a) State two ways to standardize the NaOH used in the titration. (b) Suggest and explain an indicator that can be used in the...
A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator...
A 0.704 g of a pure acid, HA, is dissolved in water and an acid-base indicator added. The solution requires 33.78 mL of 0.256 M NaOH solution to reach the end point. What is the molar mass of the acid? HA(aq) + NaOH(aq) LaTeX: \longrightarrow⟶ NaA(aq) + H2O(aq) Group of answer choices 81.4 g/mol 199 g/mol 145 g/mol 20.0 g/mol
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.762 Volume of NaOH required to reach endpoint: (ml) 18.0 pH of the mixture (half neutralized solution) 3.15 Calculate the following...
An analytical chemist weighs out 1.300 grams of an unknown monoprotic acid into a 250 mL...
An analytical chemist weighs out 1.300 grams of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark. The chemist then obtains 100 mL of the solution and titrates the 100mL of the solution with 0.1 M NaOH. When the titration reaches the equivalence point, the chemist finds he has added 24.50 mL of NaOH solution. Calculate the molar mass of the unknown
The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated...
The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated the unknown acid with a standardized NaOH solution. Unfortunately, the student over shot the end point and had to back titrate the solution with 2.17 mL of 0.98861 M HCl. Once the final end point was determined, the student had added a total of 29.15 mL of a 1.0324 M NaOH solution. A) How many moles of OH- were used to reach the end...
The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated...
The student dissolved 2.050 grams of acid in 50 mL of distilled water. He then titrated the unknown acid with a standardized NaOH solution. Unfortunately, the student over shot the end point and had to back titrate the solution with 2.17 mL of 0.98861 M HCl. Once the final end point was determined, the student had added a total of 29.15 mL of a 1.0324 M NaOH solution. A) How many moles of OH- were used to reach the end...
ABCDE ABCDE AaBbCcD ABCDE AaBb AEDEL -X, X ADA ! Normal No Spacing Heading 2 9) A student was given 0.2 g of an unknown carboxylic acid to determine its molecular weight. He/She first dissolved it into 95% ethanol, added 3 drops of phenolphthalein indicator then titrated it with standardized 0.IN NaOH solution. 15 ml NaOH was needed to reach the neutralization point. Please, answer following questions. (10 pts) a. Write down the general acid-base neutralization reaction? b. What is...
A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is titrated to a neutral endpoint with 0.10 M NaOH. The titrated portion is then mixed with the remaining untitrated portion and the pH of the mixture is measured. Mass of acid weighed out (grams) 0.773 Volume of NaOH required to reach endpoint: (ml) 19.0 pH of the mixture Ihalf neutralized solution 3.54 Calculate the following...
Data i got:
1g of solid acid=0.51706 ml
50 ml of water used to dissolve
0.5 ml of indicator added to acid solution
8.52 ml of 1M NaOH titrated from burrete into acid
solution.
The virtual lab stockroom contains NaOH, water and an unknown solid weak acid. Perform experiments to identify the pka and molar mass of the bottle of unknown solid acid. You may enter your answer in the form below the Virtual Lab NOTE: You can submit your...
A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NAOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H806 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 14.47 Concentration of NaOH in mol/L, 0.1964 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg). Answer:
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