Question

The concentration of a chemical in the bloodstream t hours after injection into muscle tissues is given by the following. C(t
C$ 1.15 C(D 0.15 0.1 0.05 1 1.5 CD 0.15 G10 1.15 005 1 1.5 2 253 0 0.5 1 1.5 2 253 t = 2.0801 hr (C) Use calculus to determin
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Answer #1

I am assuming you need solution of part C only as part A and B are correctly solved!

c(t) = 5t 1 27+t3 In order to find when the concentration, we will rese concept q maxima and minima of calcules. first deriva3 d(t) = 5 cm (2876) ckey = 5(221 at the (1274837 end (27+372 3 c(t) = 5[(27+43) (1) -+10+3t?] (274832^ct) = 5/27+63 -3 +] (27+€32 56 (t) = 5 (27 - 2+3) 127+ + 2 for maximum or minimum cl (t) = 0 = 5(27-2€ o ( 27+32 = 27-2ť =t = 3 (2)/ c(t) will be maximum at to Byte if c (és va co So, taking second derivative of c(t) c(t) = d c(t) dt-dr5(27-2+3) 7 Duoef ks 24? (29sctt) = 57(2346) (27-24) 1 -(27-28) d(27++327 - ((27+ +32 2zlity = 5 (27te) (6-2 (3) - 1 l (27-2)(2+)). (27437 (27 +23) 345(t) = 5 1-6++(27+esj?= 2(27-28). (27+€3).(0+3+²) 7 (27++3;4 at t=3 (2) 1/3| (중) - - (2) - 227-19 1태를녀름에 223 (24tN LG x 9. 3. 14 | 2f 22 el) - FI-12 )-12-3 2. (2 )()7 (27끌다 (6) - 1 2 ) - 2(2747)(27)() (27 )(0) 일) (24 ) ]re(一)--卷(!) 7(高) (4) 一 ) 十 ) = (): 本-) - - 0. 1036 le cul ) < 0 so (lt) és maximum at t = 3 21/3

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