Antimony has two naturally occuring isotopes, 121Sb and 123Sb. 121Sb has an atomic mass of 120.9038...

Question

Question

Answer 1

Answer #1

Given:

m1 = 120.9038 amu

m2 = 122.9042 amu

m = 121.7601 amu

use:

atomic mass = sum of (mass of isotope * abundance) / 100

m = (m1*A1 + m2*A2)/100

121.7601 = ( 120.9038*A1 + 122.9042*(100-A1))/100

121.7601 = ( 120.9038*A1 + 12290.42- 122.9042*A1))/100

A1 = 57.19 %

A2 = 100 - A1

= 100 - 57.19

= 42.81 %

Answer:

57.19 %

42.81 %

Answer 2

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