2. a) As 556 individuals are studied, total number of alleles will be (556 x 2) or 1112 (Because each individual will have 2 alleles).
Now, frequency of LM allele = Number of LM allele / Total number of alleles = (167 x 2 + 280) / 1112 = 614/1112 = 0.5522 (Up to 4 decimals)
So, frequency of LN allele = Number of LN allele / Total number of alleles = (109 x 2 + 280) / 1112 = 498/1112 = 0.4478 (Up to 4 decimals)
b) Under Hardy-Weinberg equilibrium-
Expected number of MM = (Frequency of LM allele)2 x Total population = (0.5522)2 x 556 = 169.54 170
Expected number of NN = (Frequency of LN allele)2 x Total population = (0.4478)2 x 556 = 111.49 111
Expected number of MN = 2 x Frequency of LM allele x Frequency of LN allele x Total population = 2 x 0.5522 x 0.4478 x 556 = 274.97 275
Now, = + + = 0.1799 (Up to 4 decimals)
Now, degrees of freedom = 1
From the distribution table we find that probability of = 0.1799 with degrees of freedom 1 falls between 0.1 & 0.9. As the probability is greater than 0.05, we can say that difference between observed & expected values are due to chance alone & no significant difference exist between them. So, the genotype frequencies fit to the Hardy-Weinberg distribution.
2. 10-points: The MN blood group in humans is under the control of a pair of...
please answer clearly so i can understand, thank you. 2. 10-points: The MN blood group in humans is under the control of a pair of co-dominant alleles LM and LN. I a group of 556 Individuals, the following genotypic frequencies are found: 167 MM 280 MN 109 NN a) Calculate the frequency of the LM and LN alleles Note: the degrees of freedom is interestingly "1" since while there are genotypes.these are determined by only 2 allelic frequencies. Our book...
Practice questions for BIO 340 (Exam 2) I need help with these questions Please. WILL GIVE GOOD RATING 1. Wild type blue-eyed mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A double heterozygote (Ww Mm) is self-pollinated. What proportion...