Part A) Which is the correct equation for the reaction of
magnesium with hydrochloric acid to produce hydrogen gas and
magnesium chloride?
Part B) Barium chloride and sodium sulfate react according to
the following equation.
BaCl2 + Na2SO4 → BaSO4
+ 2NaCl
Answer the following question(s) about this
reaction.
How many grams of barium chloride are needed to make 100. grams of
barium sulfate?
Part C) Barium chloride and sodium sulfate react according to
the following equation.
BaCl2 + Na2SO4 → BaSO4
+ 2NaCl
Answer the following question(s) about this
reaction.
How many grams of sodium chloride can be produced from 50. grams of
barium chloride?
Part D) When 25.0 g of KClO3 reacts, how many grams of
O2 are produced?
2KClO3 → 2KCl + 3O2
Express your answer using three significant figures.
Part A) Which is the correct equation for the reaction of magnesium with hydrochloric acid to...
Barium chloride and sodium sulfate react according to the following equation. BaCl2 + Na2SO4 → BaSO4 + 2Naci Answer the question(s) that follow about this reaction. How many grams of barium sulfate can be produced from 74.8 g of barium chloride?
how many grams of barium sulfate and sodium chloride are produced if 0.0298 L of 0.115 Moles of BaCl2 react completely according to the following reaction: BaCl2(aq) + Na2SO4(aq) -> BaSO4(s) + 2NaCl(aq)
how many grams of barium sulfate are produced if 25.34 mL of 0.113M BaCl2 completely react given the reaction: BaCl2(aq)+Na2SO4(aq)=BaSO4(s)+2NaCl(aq)
4) How many grams of barium sulfate are produced if 24.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2(aq) + Na2SO4(aq) BaSO4(s) + 2NaCl(aq)
2)how many moles of barium sulfate are sulfate are produced from 0.1 mole of barium chloride? b) 3 moles of BACL2 will react to produce how many moles of potassium chloride? and so on..... 2) For the balanced equation; BaCl2 + K2SO4 → BaSO4 + 2KCI a) How many mole(s) of barium sulfate are produced from 0.1 mole of barium chloride? b) 3 moles of BaCl2 will react to produce how many moles of potassium chloride? 3) For the balanced...
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 48.8 g KClO3(s).
When heated, KClO3 decomposes into KC and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 46.4 g KCl, how many grams of O2 were produced?
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 83.4 g KCl, how many grams of O2 were produced? mass: g O2
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 82.0 g KCl, how many grams of O2 were produced? mass: g O2
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 98.6 g KClO3(s). mass: