Question

tion to find moles of product from moles of reactant Ugilhon v Ammonium phosphate ((NH4), PO.) is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid (H;PO,) with liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 0.90 mol of phosphoric acid. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits. n- e 60 non X ?

Answer 1

Answer -

Given,

Moles of Phosphoric Acid (H₃PO₄) = 0.90 mol

Moles of Ammonium Phosphate produced = ?

The reaction is,

H₃PO₄ (aq) + 3 NH₃ (l) $\rightarrow$ (NH₄)₃PO₄ (s) [BALANCED]

Using Stiochiometry, it can be analyzed that for 1 mole of H₃PO₄, 1 mole of Ammonium Phosphate [ (NH₄)₃PO₄ ] is produced. i.e.

Moles of  Ammonium Phosphate [(NH₄)₃PO₄] produced = Moles of H₃PO₄

Moles of  Ammonium Phosphate [(NH₄)₃PO₄] produced = 0.90 mol [ANSWER]