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Use the equation: to write the mole ratio needed to calculate: (a) moles of KCI produced...
calculations for mole ratio on KCLO3, KCL, and O2 and explanation on how to do it...
calculations for mole ratio on KCLO3, KCL, and O2 and
explanation on how to do it so I can better understand. please and
thank you.
I thought you can only do mole ration if you have an equation and
after you balance. I'm so confused.
Result CALCULATIONS: Quantity Show Calculation Moles of KCIO 1.9799 x mol 9 122.558 Moles of KCI 11.196gx mol = 0.01615 mol = 0.01604 mol 74.559 mol 32.000 0.783g Moles of O2 = 0.2446 0.225 0.0245...
a Consider the balanced chemical equation 4Cr(s) + 302(g) + 2Cr2O3(s) What mole ratio would you...
a Consider the balanced chemical equation 4Cr(s) + 302(g) + 2Cr2O3(s) What mole ratio would you use to calculate how many moles of oxygen gas would be needed to react completely with a given number of moles of chromium metal? 4 mol O2 3 mol Cr 2 mol O2 3 mol Cr 3 mol O2 2 mol Cr 3 mol O2 4 mol Cr b Consider the balanced chemical equation 4Cr(s) + 302 (9) + 2Cr2O3(s) What mole ratio would...
calculate all required B. Percentage of potassium chlorate in a mixture (potassium chlorate+ KCI) IL Mass...
calculate all required
B. Percentage of potassium chlorate in a mixture (potassium chlorate+ KCI) IL Mass of test tube + MnO2 (catalyst, m;)-.13. 1w 3 II Mass of tube + MnO2 +mixture (before heating, ma) =..55.6.39. III Mass of tube + MnO2 + mixture (after heating, m) . .. M.Ami 16/o6/20r 2KCIO3+ (KCI) Heat Ma 2KCI+(KCI)+302 IV Mass of mixture m2- m...8.15.. ..g V. Mass of oxygen m2-m3=..A.2ol mass of oxygen Molecular weight of 0z Moles of oxygen VI. 32...
The ratio obtained from the coefficients in a balanced chemical equation is called the mole ratio. Use the balanced chem...
The ratio obtained from the coefficients in a balanced chemical equation is called the mole ratio. Use the balanced chemical reaction shown in model 2 to answer the following questions. 1. What is the mole ratio for the reaction in model 2 and explain why this is called a mole ratio. 2. If 0.052 mol N2 are reacted, how many mol NH3 are formed? Using dimensional analysis, show how you calculated your answer. 3. If 0.052 mol N2 are reacted,...
Incorrect. Did you use the appropriate mole ratio of aluminum oxide to oxygen? How many moles...
Incorrect. Did you use the appropriate mole ratio of aluminum oxide to oxygen? How many moles of aluminum oxide will be produced from 0.50 mol of oxygen? 4A1+302→ 2 Al2O3 mol Al203 the tolerance is +/-2%
8. Use the balanced equation for the reaction of N, and o, to form NO to...
8. Use the balanced equation for the reaction of N, and o, to form NO to answer each question. N2+O2---->2No a. How many moles of NO are formed from 3.3 mol of N? b. How many moles of NO are formed from 0.50 mol of O? c. How many moles of O2 are needed to completely react with 1.2 mol of N ?
Calculate molar ratios Question Given the following equation, 2 KCIO; — 2 KCI + 3 02...
Calculate molar ratios Question Given the following equation, 2 KCIO; — 2 KCI + 3 02 how many moles of O2 can be produced from 8.60 moles KCIO,? • Report your answer with three significant figures Provide your answer below:
7.3 The Mole Concept in Balanced Equations The Mole Map Mole Ratio From Equation Molar Mass...
7.3 The Mole Concept in Balanced Equations The Mole Map Mole Ratio From Equation Molar Mass Molar Mass Moles BGrams B Grams A Moles A Avogadro's Number Avogadros Number Particles A Particles B Consider the following generic reaction If a chemist carries out this reaction using 11.0 moles of A, 8. a. How many moles of B are needed? b. How many moles of C can form? 9. Potassium metal reacts with water according to the balanced equation shown: 2...
I need help with part B Explanation: A mole ratio is the ratio between the amounts in moles of any two compounds invol...
I need help with part B
Explanation:
A mole ratio is the ratio between the amounts in moles of any
two compounds involved in a chemical reaction. The mole ratio can
be determined by examining the coefficients in front of formulas in
a balanced chemical equation.
Step 1: write the balanced chemical
equation.
Sb2S3(s) + 3Fe(s)→2Sb(s) +3FeS(s)
Step 2: calculate the moles of
Sb2S3 , Fe
Moles of Fe = mass given / molar mass = ( 25 g
/...
2)how many moles of barium sulfate are sulfate are produced from 0.1 mole of barium chloride?...
2)how many moles of barium sulfate are sulfate are produced from
0.1 mole of barium chloride?
b) 3 moles of BACL2 will react to produce how many moles of
potassium chloride?
and so on.....
2) For the balanced equation; BaCl2 + K2SO4 → BaSO4 + 2KCI a) How many mole(s) of barium sulfate are produced from 0.1 mole of barium chloride? b) 3 moles of BaCl2 will react to produce how many moles of potassium chloride? 3) For the balanced...
calculations for mole ratio on KCLO3, KCL, and O2 and
explanation on how to do it so I can better understand. please and
thank you.
I thought you can only do mole ration if you have an equation and
after you balance. I'm so confused.
Result CALCULATIONS: Quantity Show Calculation Moles of KCIO 1.9799 x mol 9 122.558 Moles of KCI 11.196gx mol = 0.01615 mol = 0.01604 mol 74.559 mol 32.000 0.783g Moles of O2 = 0.2446 0.225 0.0245...
a Consider the balanced chemical equation 4Cr(s) + 302(g) + 2Cr2O3(s) What mole ratio would you use to calculate how many moles of oxygen gas would be needed to react completely with a given number of moles of chromium metal? 4 mol O2 3 mol Cr 2 mol O2 3 mol Cr 3 mol O2 2 mol Cr 3 mol O2 4 mol Cr b Consider the balanced chemical equation 4Cr(s) + 302 (9) + 2Cr2O3(s) What mole ratio would...
calculate all required
B. Percentage of potassium chlorate in a mixture (potassium chlorate+ KCI) IL Mass of test tube + MnO2 (catalyst, m;)-.13. 1w 3 II Mass of tube + MnO2 +mixture (before heating, ma) =..55.6.39. III Mass of tube + MnO2 + mixture (after heating, m) . .. M.Ami 16/o6/20r 2KCIO3+ (KCI) Heat Ma 2KCI+(KCI)+302 IV Mass of mixture m2- m...8.15.. ..g V. Mass of oxygen m2-m3=..A.2ol mass of oxygen Molecular weight of 0z Moles of oxygen VI. 32...
Incorrect. Did you use the appropriate mole ratio of aluminum oxide to oxygen? How many moles of aluminum oxide will be produced from 0.50 mol of oxygen? 4A1+302→ 2 Al2O3 mol Al203 the tolerance is +/-2%
8. Use the balanced equation for the reaction of N, and o, to form NO to answer each question. N2+O2---->2No a. How many moles of NO are formed from 3.3 mol of N? b. How many moles of NO are formed from 0.50 mol of O? c. How many moles of O2 are needed to completely react with 1.2 mol of N ?
Calculate molar ratios Question Given the following equation, 2 KCIO; — 2 KCI + 3 02 how many moles of O2 can be produced from 8.60 moles KCIO,? • Report your answer with three significant figures Provide your answer below:
7.3 The Mole Concept in Balanced Equations The Mole Map Mole Ratio From Equation Molar Mass Molar Mass Moles BGrams B Grams A Moles A Avogadro's Number Avogadros Number Particles A Particles B Consider the following generic reaction If a chemist carries out this reaction using 11.0 moles of A, 8. a. How many moles of B are needed? b. How many moles of C can form? 9. Potassium metal reacts with water according to the balanced equation shown: 2...
I need help with part B
Explanation:
A mole ratio is the ratio between the amounts in moles of any
two compounds involved in a chemical reaction. The mole ratio can
be determined by examining the coefficients in front of formulas in
a balanced chemical equation.
Step 1: write the balanced chemical
equation.
Sb2S3(s) + 3Fe(s)→2Sb(s) +3FeS(s)
Step 2: calculate the moles of
Sb2S3 , Fe
Moles of Fe = mass given / molar mass = ( 25 g
/...
2)how many moles of barium sulfate are sulfate are produced from
0.1 mole of barium chloride?
b) 3 moles of BACL2 will react to produce how many moles of
potassium chloride?
and so on.....
2) For the balanced equation; BaCl2 + K2SO4 → BaSO4 + 2KCI a) How many mole(s) of barium sulfate are produced from 0.1 mole of barium chloride? b) 3 moles of BaCl2 will react to produce how many moles of potassium chloride? 3) For the balanced...
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