Question

Find the integral per proton, number of repeating monomer units (n), and Mn for the following 1H-NMR Spectra:

Example 4 186.00 4.00 1.00 dc CDCI 30 28 26 si o / ppm

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Answer #1

Looking at the structure, we can tell that signal b corresponds to 3 protons and signals c and d correspond to 4 protons each. This means that the integration corresponding to each proton has a value of 0.25. Knowing this, we can determine the amount of protons that make up the signal for a:

186 -= 744 protons 0.25 proton

Each monomer contains four protons, which make up the signal. This means that the number of repeating units is:

744protons -= 186 units unit 4 protons

There are 186 repeating units (n) in this polymer.

The Mn is composed by the weight of things outside of the repeating unit: 224 g/mol

And the mass of the repeating unit multiplied by 186: 44 * 186 = 8184 g/mol

Making the total Mn: 8408 g/mol.

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