Question

the answer is a but please explain why

W jennajulien - lets build a raft + + le Docs Academic Boosters Scholarship E X -4367715/viewContent/5877824Niew?u=4367715 11. These molecular scenes represent three mixtures in which A (black) and B (green) are forming AB. Each molecule represents 0.10 atm. The equation is A2(g) + B2(g) 2AB(g) and AGⓇ = -3.4 kJ/mol for the reaction as described by the equation. Choose the correct statement. (a) If Mixture 1 is at equilbrium, the reaction temperature must be 295 K. (b) If Mixture 2 is at equilbrium, the reaction temperature must be 295 K. (C) If Mixture 3 is at equilbrium, the reaction temperature must be 295 K. (d) None of the above is correct. t 4 17

Answer 1

Sol. As we known, Alg) +B (g) 2AB (g) AG = AG + RT en 10 = DG + RT ln [AB]² LG = - RT en kage ki [AD]² {^3 [0] Put Concentration are in pressure boom, [AB] = Pro J² (A) = Pa [B] = Post DG = -RT ln (PAD)' (PA) (P) From fig. I we can see that 4 moles of AB 2 molecules of A 2 molecules of B Pressure of each molecule = 0.10 atm. Soe Pressure of AB = 4 X0.10 = 0.4 Pressure of A = 2X0.150.2 Pressure of B = 2X0.1= .0.2 From equ o -3.4 x103 J mol = -8.314 XT en 0.4) 16.2)* (0.2) -3.4 x103 = -8.314 XT X en 4 I = 3400 = 3400 = 295.014 8314 lu 4 8.314X1.3862 T = 295.014 ~ 295K. Therefore temperature for fig 1. is 295 which is option A. Method II - - First we put the value of T in conation 0 and then Check value of K . The figure which satisfies the value of K. the Option. Scanned with CamScanner K