a)
it is two tail test
Ho : µ = 140
Ha : µ ╪ 140
b)
sample std dev , s = √(Σ(X- x̅ )²/(n-1) )
= 15.0000
Sample Size , n = 4
Sample Mean, x̅ = ΣX/n =
162.5000
degree of freedom= DF=n-1= 3
Standard Error , SE = s/√n = 15.0000 / √
4 = 7.5000
t-test statistic= (x̅ - µ )/SE = ( 162.500
- 140 ) / 7.500
= 3
c)
critical t value, t* = ±
2.3534 [Excel formula =t.inv(α/no. of tails,df)
]
d)
p-Value = 0.0577 [Excel
formula =t.dist(t-stat,df) ]
e)
Decision: p-value<α, Reject null hypothesis
f)
since, null hypothesis is rejected , Type II error could not be
committed.
Problem 6 (20 Points) One-Sample Hypothesis Nancy believes that the average running time of movies is...
QUESTION 22 Nancy believes that the average running time of movies is equal to 140 minutes. A sample of 4 movies was taken and the following running times (in minutes) were obtained. Assume the population of the running times is normally distributed. 150 150 180 170 Test the hypotheses at the 10% level of significance. The p-value is between .50 to 10; accept HO Accept HO because test statistics t = 3 > 2.353 Reject HO because test statistict -...
QUESTION 16 Your instructor (Katie) believes that the average time of taking this is equal to 140 minutes. A sample of 4 students was taken and the following times were obtained. Assume the distribution of the population is normally distributed. Sample: 150, 150, 180, 170 (Sample Std. Dev = 15) The critical value for this test at a 0.1 level of significance is: a. 1.638, -1.638 b. 1.645, -1.645 c. 2.353, -2.353 d. 1.285, -1.285 Your instructor (Katie) believes that...
Your instructor (Katie) believes that the average time of taking this exam is equal to 140 minutes. A sample of 4 students was taken and the following exam times were obtained. Assume the distribution of the population is normally distributed. Sample: 150, 150, 180, 170 (Sample Std. Dev = 15) The critical value for this test at a 0.1 level of significance is: O a. 1.285.-1.285 O b.2.353,-2.353 1.645,-1.645 OC. d. 1.638,-1.638
Your instructor (Katie) believes that the average time of taking this test is equal to 140 minutes. A sample of 4 students was taken and the following test times were obtained. Assume the distribution of the population is normally distributed. Sample: 150, 150, 180, 170 (Sample Std. Dev = 15) (1) The critical value for this test at a 0.1 level of significance is: a. 1.285, -1.285 b. 1.645, -1.645 c. 1.638, -1.638 d. 2.353, -2.353 (2) At a 0.1...
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