Q= 1.2C, d= 10cm, I= 10A. The direction of v is perpendicular to I. If v=0...
Q= 1.2C, d= 10cm, I= 10A. The direction of v is perpendicular to I. If v=0 m/s, what is the magnetic force acting on charge Q? If v= 13m/s, what is the magnetic force acting on charge Q? what direction is the force on Q?
Homework Answers
if v = 0
magnetic force acting on charge F = QvB sin(theta) = 0
-----------------------
if v = 13 m/s
magnetic field at distance d= 10 cm = 0.1 m
B = Mu0*i/(2pid) = 4pix10^-7*10/(2pi*0.1) = 2x10^-5 T
magnetic force acting on charge , F = 1.2*13* 2 x 10^-5 = 3.12 x10^-4 N
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