Question

1. The hydroxide ion (OH-) catalyzes the reaction below, and rate data was obtained: OCI + ----> OI + Cl Experiment # [OCI].
0 0
Add a comment Improve this question Transcribed image text
Answer #1

& Accolding to law of mass action: Exc. Rate o Ex - 3 Exer [cum [F] Rate 0.00184 - scooth (0.goo 0.00184 (0.002) corror 1.000. from Eup. , ; & il you change only Ców: Rate not effected : Gr is catalyst. in Rate & cöces ca] Kate = k roce [2] : (ii) From .

Add a comment
Know the answer?
Add Answer to:
1. The hydroxide ion (OH-) catalyzes the reaction below, and rate data was obtained: OCI +...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Use the data on the next slide for the reaction of hypochlorite ion with iodide ion...

    Use the data on the next slide for the reaction of hypochlorite ion with iodide ion in 1M aqueous hydroxide solution: OCl- + I- -> OI- + Cl- The answer is 68.5, but I do not understand how to get the answer. Mar 2 Chapter 15 Chemical Kinetics er 15 Chemical Kinetics Chaoter 16 Chemical Equilibrium Chapter 17 Acids and Bases Practice Problem Use the data on the next slide for the reaction of hypochlorite ion with iodide ion in...

  • 1- In the presence of excess OH-, the Zn2+(aq) ion forms a hydroxide complex ion, Zn(OH)42-....

    1- In the presence of excess OH-, the Zn2+(aq) ion forms a hydroxide complex ion, Zn(OH)42-. Calculate the concentration of free Zn2+ ion when 1.32×10-2mol ZnSO4(s) is added to 1.00 L of solution in which [OH- ] is held constant (buffered at pH 12.40). For Zn(OH)42-, Kf = 4.6×1017. [Zn2+] = ------ M 2- What is the approximate concentration of free Hg2+ ion at equilibrium when 1.86×10-2 mol mercury(II) nitrate is added to 1.00 L of solution that is 1.310...

  • Consider this initial rate data at a certain temperature in the table for the reaction OH(aq)...

    Consider this initial rate data at a certain temperature in the table for the reaction OH(aq) OCI-(aq+ I (aq) — 01 (aq) + Cl(aq) [OCI-] [I] Trial (M) (M) 1 0.00161 0.00161 2 0.00161 0.00287 3 0.00304 0.00161 4 0.00161 0.00287 [OH-] (M) 0.470 0.470 0.620 0.761 Initial rates (M/s) 0.000283 0.000504 0.000405 0.000311 Determine the rate law. Answer Bank [ocr] [1] rate =k [1-12 [OCIJ? [OH] [OH)2 Determine the value of the rate constant for this reaction and the...

  • The following data was collected at 20C for the reaction of bromphenol blue (HBPB2-) and hydroxide...

    The following data was collected at 20C for the reaction of bromphenol blue (HBPB2-) and hydroxide ion (OH-), shown in the equation. HBPB2- + OH- BPB3- + H2O The times required to consume a small but constant amount of HBPB2- at varying initial HBPB2- and OH- concentrations were measured and are recorded below. Determination [HBPB2-], M [OH-], M Time, s 1 7.22 x 10-6 1.00 75 2 7.22 x 10-6 0.25 290 3 3.63 x 10-6 1.00 152 a) Determine...

  • can you help me with this question please 6. The following data refer to the hydrolysis...

    can you help me with this question please 6. The following data refer to the hydrolysis of 2-bromo-2-methylpropane, by aqueous sodium hydroxide at 25 °C. (CH3)3CBr+ OH -(CHa) COH + Br Experiment # Concentration of Concentration of Initial rate of 2-bromo-2- hydroxide ions (M) hydrolysis (M/'s) methylpropane (M) 1 0.100 0.500 0.0020 2 0.100 0.250 0.0020 3 0.075 0.250 0.0015 4 0.050 0.250 0.0010 5 0.025 0.250 0.0005 What is the order of reaction with respect to a. i. 2-bromo-2-methylpropane...

  • Answer with explanation. ASAP please 02 DU 3. The reaction below gave the following data in...

    Answer with explanation. ASAP please 02 DU 3. The reaction below gave the following data in an experiment that was NOT well-designed. OH- ClO-(aq) + (aq) ---> Cl(aq) +10-(aq) Initial concentrations Trial (CIO), M [1],M [OH-], M Initial Rate, M/s 2.0 x 10-3 2.0 x 10-3 1.00 2.42 x 10-4 3.0 x 10-3 2.0 x 10-3 1.00 3.60 x 10-4 4.0 x 10-3 4.0 x 10-3 1.00 9.40 x 10-4 2.0 x 10-3 2.0 x 10-3 0.50 4.75 x 10-4...

  • Question 17 (3 points) The following set of data was obtained by the method of initial...

    Question 17 (3 points) The following set of data was obtained by the method of initial rates for the reaction: (H3C)3CBr + OH- → (H3C)3COH + Br- [(H3C)3CBr] (M) [OH-] (M) Initial Rate (M/s) 0.25 0.25 1.1 x 10-4 0.50 0.25 2.2 x 10-4 0.50 0.50 2.2 * 10-4 What is the rate law for this reaction, including the value for the rate constant k? You may omit units. Question 18 (3 points) For a particular first-order reaction, it takes...

  • 1. TL .lowing te deta was obtained experimentally. Rxn: A +28. 3 . D Rate (M/S)...

    1. TL .lowing te deta was obtained experimentally. Rxn: A +28. 3 . D Rate (M/S) (M) [B] (M) C (M) 2.0 2056 0.050 0.20 2.0 0.050 0.10 0.20 50 0.25 0.10 0.20 16 0.050 0.40 a. Determine the rate law expression for this reaction (15 pts). Rate 4 = 0.40 = K [65[o oboJo no 2 - 8 Rate 2 0 .20 2 K[2[650[ 10 0.10 'b. What is the value for the rate constant (with proper units) (5...

  • Consider the reaction: 2 HgCl2 (aq) + C2O42-(aq)  2 Cl-(aq) + 2 CO2 (g) + Hg2Cl2(s) The initial rate of this reaction was determined for several concentrations of mercury (II) chloride and oxalate io...

    Consider the reaction: 2 HgCl2 (aq) + C2O42-(aq)  2 Cl-(aq) + 2 CO2 (g) + Hg2Cl2(s) The initial rate of this reaction was determined for several concentrations of mercury (II) chloride and oxalate ion and the following rate data was obtained: Experiment HgCl2 (aq) ( mol/L) C2O42-(aq) (mol/L) Rate (mol/L-s) 1 0.164 0.15 0.000032 2 0.164 0.45 0.00029 3 0.082 0.45 0.00014 4 0.246 0.15 0.000048 What is the rate law for the reaction? What is the value of...

  • For the reaction of B with hydroxide ion, the following initial rate data are found: [B]...

    For the reaction of B with hydroxide ion, the following initial rate data are found: [B] (mol L-1) [OH-] (mol L-) Rate (mol L-4 s=1) 0.0100 1.0 x 10-4 1.2 x 10-3 0.0100 1.0 x 10-2 1.2 x 10-1 0.0025 1.0 x 10-2 3.0 x 10-2 What will the rate be when [Blo = 0.00100 M and [OH-] = 0.10 M in mol L-15-1? O A. 0.24 O B. 0.06 O C. 0.30 O D. 0.12 O E. 0.18

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT