Chapter 19, Problem 053 Suppose 2.58 mol of an ideal diatomic gas, with molecular rotation but...

Question

Question

Answer 1

Answer #1

f = 4 for this kind of gas.

(A) Q = n cp deltaT

Q = 2.58 (4/2 + 1)(8.314)(61.4)

Q = 3951 J

(B) change in internal energy = n Cp deltaT

= 2.58 x 2 x 8.314 x 61.4

= 2634 J

(C) Work done = n R deltaT

= 2.58 x 8.314 x 61.4

= 1317 J

(d) deltaK = (3/2)n R T

= 1975.5 J

Answer 2

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