Question

For Questions 3, 4, 5, and 6.... You are pushing a filing cabinet horizontally across a rough floor (Hk = 0.44) in a straight line at a constant speed. 3. [0.25 pts] Fill in the blank. ... The force that you exert on the filing cabinet will be the frictional force on the cabinet a. less than b. equal to c. more than than its weight 4. [0.25 pts] Fill in the blank.... The force that you exert on the filing cabinet will be a. less than b. equal to more than 5. [0.25 pts] If you exerted twice the force, the cabinet would slide at a constant speed that is twice the original value. a. True b. False 6. [0.25 Points] If you exerted twice the force, the cabinet would accelerate across the floor. a. True b. False

Answer 1

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Solution- no motion 3.) Here, the cabinet is moving at a constant speed that means there is net acceleration produced. So, newton's first law og applies here. ay ΣΕ -Ο >F F- f = 0 fe x So, F=f can see that applied force the fictional force. So, option (b.) is the is equal to correct answer We know that frictional force depends on normal force and here normal force is equal to the weight of the cabinet. No not acceluation in vertical deration, so, Efy = 0 w N- W=0 IN=w Now, f HAN - 0.44W So, fait we multiply 8.44 to w it reduces the force. So, & friction force becomy

leu than W. Fiction force is also equal to applied force So, I also becomes less than w.. Sog option (a) is the correct one. find out if become Ef equals some other So, force zero Ef = 2F - f from (3) we know that F = f. So, we Can see 2f- f f Here, that Ef equals to a force magnitude is equal to the magnitude frictional force. So, there is net acceleration So, option (6.) is corrut. 영 (a.) is correet.