Question
Answer : 8.66 ns
uppose an object with a rest length of 10 ns is at rest in a frame that is moving with a speed of 0.50 relative to the Home Frame. Draw a two-observer spacetime dia- gram of this situation, and use it to determine the length of the object in the Home Frame. Check your result by using equation R6.2.
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Answer #1

LR = 10 ns

β = 0.5

Then

L = LR*sqrt[1 - β2] = 10*sqrt[1 - 0.5^2] = 8.66 ns

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