Question

PLEASE READ THE NOTE AND FOLLOW FOR THE RIGHT ANSWER !!

"Polar form needs to be in V=[dr/dt](er)+(r)[d theta/dt](e theta) as shown in the red pen writing. You did not do this for the question that is why you got is wrong.

Then for cartesian er=cos(theta)i+sin(theta)j and e(theta)=-sin(theta)i+cos(theta)j. Substitute these two question for er and e(theta) and multiply them by dr/dt and (r) d theta/dt. Add all the i and all the j and you will get your final answer as shown in the red pen writing"

W rad's 1COS(O) ft Determine: velocity when Cartean ordinates - 50 degrees in polar coordinates and 2) in Pilar cuordinates AT am cir Van Ecole valeurs reo V= [ (H0.1 cos co ft] xq Stud: O 5120 x4 V LO.IX I X-sin 10 v=1-0l sin (0) } x 4 v=-0.6844. flis b) in cartesian coordinates V=xi tys Vrcoso ir sinoj r= (toolcos Colcosoit (1+0. I cosco) sino- 4+0 - Vio V-0.684 1 +0,9152 ;

Answer 1

Answer:)

We have been given that :

= 9 rad/s

re) = 1 + 0.1 cos

This means that :

dr at dr do do dt = = (-0.1 sin ). (9) = -0.9 sin

and

do = (1 + 0.1 cose). 9 = 9+0.9 cos

Thus, we have, in general :

v= -0.9 sin lê+(9 +0.9 cos é

Specifically, when , we get that :

209 = 0

v = -0.9 sin 50°ê, + (9 +0.9 cos 50°), = -0.6894ê, +9.5785em

In Cartesian coordinates, we have :

ê= cos +sin oj ég = – sin fî + cos oj

Thus, we have :

v= -0.6894(cos 50°i + sin 50°j) +9.5785( - sin 50'i + cos 50°)

Which comes out to be :

v= -7.7807î + 5.6288;