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Please help determining this structure and explain how you got to that structure please because I’m lost



IR Spectrum 3000 1600 1200 conjug UV Spectrum V (cm) Mass Spectrum λmax 217nm (log10ε 4.1) solvent: mechanol M+ 112 C5H403 口-4-81294 40 80 120 160200 240 280 13C NMR Spectrum (100.0 MHz, CDCI, soktion) no CHz proton decoupled 200 160 120 80 40 0 δ(pp H NMR Spectrum (400 MHz, CDC, sokudion) Zpea 3h 6.75 6.70 ppm 225 2.20 ppm ET 10 9 6
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IR peaks at 1845 cm - and 1768 cm1 shows the prescence of anhydrde THe unsaturation is 4 as you calculated. In C13 peak at 13

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