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Image for 7) A blood flow monitor uses a 0.5T field applied to a blood vessel perpendicular to the flow and measures the

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Answer #1

Here ,

as speed , u = 0.3 m/s

and d = 2 mm = 0.002 m

Now , for zero force ,

quB = qE

E = 0.3 * 0.5

E = 0.15 V/m

Now , for finding the potential

V = E.d

E = 0.15 * 0.002

E = 3 *10^-4 V

the potential difference is 3 *10^-4 V

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