Question

The electric flux density produced inside a parallel plate capacitor with a 3 cm diameter and plate separation of 60mm is)--4.5 cos(20π×103t) az c. Use Ampere's Law in point form to determine the following a. The curl of the magnetic field intensity due to displacement current produced in the capacitor. Plot the magnitude of the curl of the magnetic field intensity versus the magnitude of the electric flux density produced b. in the capacitor for S ts 10 msec.

Answer 1

Given that capacitor with a 3cm diametric and plate separation of 60mm D = -4.5 cos (20 pi times 10^+ 3 t) a_z nc/m^2 {electric flux density} (a) from amperes law del times B = leo j + u_0 partial differential D/ partial differential t since, j = 0 for capacitor space del times B = mu_0 d D/dt D is the only function of time so, absolute derivation del times B = mu_0 (+ 4.5 times 20 pi times 10^3) sin (20 pi times 10^3 t) = 4 pi times 10^-7 times 4.5 times 20 pi times 10^+ 3 sin (20 pi times 10^3 t) = 4 times (3.14)^2 times 4.5 times 20 times 10^-4 sin (20 pi times 10^3 t) del times B = 355 sin (20 pi times 10^3 t) (b) plot of del times B since frequency is same for both graph but magnitude is different and phase w = 62800/sec