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In another key reaction in glycolysis, phosphate

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Answer #1


part A

DG0 = -RTlnKeq

7.5*10^3 = -(8.314*(37+273.15))lnk

keq = 5.4*10^(-2)

part B

from equation

Keq = [GAP]/[DHAP]

So that, Keq will be less than zero.there fore DG is +ve always.

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