Question

A copper/magnesium electrochemical cell was constructed.

EXPERIMENT S Volumetric Analysi Acid-Bse Titration Part Il: Answer each of the following questions about the copper/magnesium electrochemical cell you built in this experiment. Answer for the single cell, do not worry about the series configuration. 65 Copper Which electrode is the cathode? Magnesium Copper Which electrode is the anode? 2 Magnesium 3. Write the equation for the half-reaction that occurs at the copper electrode, and indicate whether it is an oxidation or a reduction reaction: Half-reaction: (circle one) Reduction Oxidation It is: 4 Write the equation for the half-reaction that occurs at the magnesium electrode, and indicate whether it is an oxidation or a reduction reaction: Half-reaction: It is Oxidation Reduction (circle one)

Answer 1

In copper/magnesium electrochemical cell, copper will undergo reduction and Magnesium will undergo oxidation as we know that the metal ion having higher redcution potential undergoes reduction and the other will undergo oxidation. Here con cut cu has higher reduction potential so it will undergo reduction . we also know that the electrode where reduction occurs is Cathode and the electrode where oxidation occurs is anode. so (2) The electo de which is cathode is - Copper. (2) The electrode which is anode is - Magnesium. (3) The reaction that occurs at copper electoole is 1 Cu2+ (aq) + 26 Cu (s) It is a reduction reaction as electrons are gained. (4) Reaction at Magnesium electrode - Mg(s) might caq.) the It is an oxidation reaction as electrons are Costa