First, note that there is no PCl5
so we need to get rid of PCl5
the best will be to invert (b) since it has PCl3 and we need it in th eproduct side
so
P + 5/2Cl2 = PCl5 Ka
PCl5 = PCl3 + Cl2 1/Kb
add both equaitons
PCl5 + P + 5/2Cl2 = PCl5+ PCl3 + Cl2 Ka * 1/Kb
cancel common terms
P + 5/2Cl2 = PCl3 + Cl2 K total = Ka * 1/Kb
Q2.
now...
Krequired = [H2]^0.5 * [Br]^0.5 / [HBr]
from the data:
for
i)
H2 + Br = 2HBr
this is: inverted, and multiplied by 4
so
Keffect = (1/K)^4
ii)
this is: just inverted so
Keffect = 1/K
iii)
this is:
multiplied just by 2 so
Keffect = K^2
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