![QUESTION 55 - WRITE YOUR ANSWER IN THE SPACE PROVIDED [5 marks] For the equilibrium reaction: PC1s(g) = PC13(g) + Cl2(g); Kc](http://img.homeworklib.com/questions/35cd0230-7184-11ea-add9-73f530efb56e.png?x-oss-process=image/resize,w_560)
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QUESTION 55 - WRITE YOUR ANSWER IN THE SPACE PROVIDED [5 marks] For the equilibrium reaction:...
For the equilibrium reaction: PCis(g) = PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration...
For the equilibrium reaction: PCis(g) = PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PC13 and Cl2? [4marks]
Part B please For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibr...
Part B please
For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PClz and Cl ? [4marks]
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls...
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls at 250°C is 0.041 ΔH is positive; reactants and products are gases at 250°C. Refer to your textbook. 1. Is the reaction above exothermic or endothermic? 2. What happens to the concentrations of PCls and Cl if more PCls is added once the reaction reaches equilibrium? (increases, decreases) PC1s Cl2 3. What happens to the moles of PCIs, PCls and Cl in the container...
Hello, I want to learn how to solve this question. While answering it please explain step...
Hello, I want to learn how to solve this question. While
answering it please explain step by step and with
readable* writing. I sincerely appreciate the
assistance.
1.00x10-3 mol PCls is introduced into a 250 ml flask and equilibrium is established at 284 °C: PC1s(g) - PC13(g) + Cl2(g) The quantity of Cl2 present at equilibrium is found to be 9.65x10-4 mol. What is the value of Kc for the dissociation reaction at 284 °C?
Consider the equilibrium between PCls, PClj and Cl2. PCIs(g)-PC13(g) + Cl2(g) K 0.251 at 571 K...
Consider the equilibrium between PCls, PClj and Cl2. PCIs(g)-PC13(g) + Cl2(g) K 0.251 at 571 K The reaction is allowed to reach equilibrium in a 15.2-L flask. At equilibrium, [PCIs]-9.75x102 M, [PCl,]-o.156 M and [C12] = 0.156 M. (a) The equilibrium mixture is transferred to a 7.60-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 7.60-L flask. [PCI5] [C12] =
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g)...
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If 0.1050 mol of PCL5, 0.0450 mol of Cl2 and 0.0450 mol of PCl3 is placed in a 0.5000-L flask at 250°C, what are the equilibrium concentrations of PCl3 and Cl, if equilibrium (PCI5] = 0.2065 M? A) [PC13] = 0.00350 M; (Cl2] = 0.00350 M B) [PC13] = 0.0900 M; [Cl2] = 0.0900 M -=51,85 (66450) (19450) C) [PC13] = 0.2100 M; [Cl2] =...
Consider the reaction. PCI; (g) = PCI,(g) + Cl2(g) Kc = 0.0420 The concentrations of the...
Consider the reaction. PCI; (g) = PCI,(g) + Cl2(g) Kc = 0.0420 The concentrations of the products at equilibrium are [PC13] = 0.160 M and [Cl2] = 0.160 M. What is the concentration of the reactant, PCs, at equilibrium? [PCI31= C [PCIS] = M
Consider the equilibrium reaction at 100°C: 2NO(g) + O2(g)⇌ 2NO2(g); KC = 30,000 a. Write the concentration equilibrium equation for the reaction. [1 b. If 46 grams of NO2(g) is introduced into a 1 L flask what will be the equilibrium concentrations of NO
Consider the equilibrium reaction at 100°C:2NO(g) + O2(g)⇌ 2NO2(g); KC = 30,000Write the concentration equilibrium equation for the reaction. If 46 grams of NO2(g) is introduced into a 1 L flask what will be the equilibrium concentrations of NO2, O2 and NO?
please write clear and complete. 7. The equilibrium constant at a particuiar temperature for the reaction:...
please
write clear and complete.
7. The equilibrium constant at a particuiar temperature for the reaction: H2(g) + Br2(g) -> 2HBr(g) is 1.5 x 105 The value of Kc for HBr(g) -1 /2 H2(g) + 1 /2 Br2(g) is PCla(g) + Cl2(g) For the equilibrium: PCIs(g)-- Kc = 4.0 at 228°C. If 0.35 g of pure PC15 is added to a 2.0 L flask what will be the equilibrium concentration of Cl2(g). (you'll need to carry extra sig figs to...
For the equilibrium reaction: PCis(g) = PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PC13 and Cl2? [4marks]
Part B please
For the equilibrium reaction: PCI (g) =PC13(g) + Cl2(g); Kc = 0.00183 a. Write the concentration equilibrium equation for the reaction. [1 mark] b. If 2.0 gram of PCis(g) is introduced into a 1.5 L flask what will be the equilibrium concentrations of PCls, PClz and Cl ? [4marks]
Answer the questions about the following reaction below. The equilibrium constant for the decomposition of PCls at 250°C is 0.041 ΔH is positive; reactants and products are gases at 250°C. Refer to your textbook. 1. Is the reaction above exothermic or endothermic? 2. What happens to the concentrations of PCls and Cl if more PCls is added once the reaction reaches equilibrium? (increases, decreases) PC1s Cl2 3. What happens to the moles of PCIs, PCls and Cl in the container...
Hello, I want to learn how to solve this question. While
answering it please explain step by step and with
readable* writing. I sincerely appreciate the
assistance.
1.00x10-3 mol PCls is introduced into a 250 ml flask and equilibrium is established at 284 °C: PC1s(g) - PC13(g) + Cl2(g) The quantity of Cl2 present at equilibrium is found to be 9.65x10-4 mol. What is the value of Kc for the dissociation reaction at 284 °C?
Consider the equilibrium between PCls, PClj and Cl2. PCIs(g)-PC13(g) + Cl2(g) K 0.251 at 571 K The reaction is allowed to reach equilibrium in a 15.2-L flask. At equilibrium, [PCIs]-9.75x102 M, [PCl,]-o.156 M and [C12] = 0.156 M. (a) The equilibrium mixture is transferred to a 7.60-L flask. In which direction will the reaction proceed to reach equilibrium? (b) Calculate the new equilibrium concentrations that result when the equilibrium mixture is transferred to a 7.60-L flask. [PCI5] [C12] =
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC15(g) Calculate the equilibrium concentrations of reactant and products when 0.389 moles of PC13 and 0.389 moles of Cl2 are introduced into a 1.00 L vessel at 500 K [PC13] = [Cl] = [PC15] - The equilibrium constant, Kc, for the following reaction is 5.10x10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.467 moles of NHACI(S)...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If 0.1050 mol of PCL5, 0.0450 mol of Cl2 and 0.0450 mol of PCl3 is placed in a 0.5000-L flask at 250°C, what are the equilibrium concentrations of PCl3 and Cl, if equilibrium (PCI5] = 0.2065 M? A) [PC13] = 0.00350 M; (Cl2] = 0.00350 M B) [PC13] = 0.0900 M; [Cl2] = 0.0900 M -=51,85 (66450) (19450) C) [PC13] = 0.2100 M; [Cl2] =...
Consider the reaction. PCI; (g) = PCI,(g) + Cl2(g) Kc = 0.0420 The concentrations of the products at equilibrium are [PC13] = 0.160 M and [Cl2] = 0.160 M. What is the concentration of the reactant, PCs, at equilibrium? [PCI31= C [PCIS] = M
please
write clear and complete.
7. The equilibrium constant at a particuiar temperature for the reaction: H2(g) + Br2(g) -> 2HBr(g) is 1.5 x 105 The value of Kc for HBr(g) -1 /2 H2(g) + 1 /2 Br2(g) is PCla(g) + Cl2(g) For the equilibrium: PCIs(g)-- Kc = 4.0 at 228°C. If 0.35 g of pure PC15 is added to a 2.0 L flask what will be the equilibrium concentration of Cl2(g). (you'll need to carry extra sig figs to...
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