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5. Lead has a density of 10.5 g/cm3. What is the diameter of a lead ball that has a mass of 500.0 g? Report your answer in cm
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Answer #1

Volume of ball (sphere) = (4/3) * π * r^3 ----(1)

π = constant = 3.14 , r = radius

We also know Density * Volume = mass

10.5 g/cm^3 * (4/3) * 3.14 * r^3 = 500.0 g

43.96 cm^-3 * r^3 = 500.0

r^3 = 500.0 / 43.96 cm^-3 = 11.37 cm^3

r = (11.37)^1/3 = 2.25 cm

Diameter = 2 * radius = 2 * 2.25 cm = 4.50 cm

Diameter of lead = 4.50 cm

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