Question

A 290-kg load is lifted 24.0 m vertically with an acceleration a=0.180 g by a single...

A 290-kg load is lifted 24.0 m vertically with an acceleration a=0.180 g by a single cable.

Part A

Determine the tension in the cable.

FT =   N  

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Part B

Determine the net work done on the load.

Wnet =   J  

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Part C

Determine the work done by the cable on the load.

Wcable =   J  

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Part D

Determine the work done by gravity on the load.

WG =   J  

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Part E

Determine the final speed of the load assuming it started from rest.

v =   m/s  
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Answer #1

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