Question

1) Which of these scenarios would not produce seedless fruits?

a) Plants with mutation(s) that cannot develop fertile embryos are propagated by grafting, then treated with a hormone to develop fruit

b) Triploid plants with a parthenocarpy gene

c) Plants with parthenocarpy gene growing in orchards of clones that are self-incompatible by S-gene recognition

d) A scion or bud from one plant is grafted on to another plant to produce the desired fruit variety

Answer 1

Out of the given options, option d is the correct answer.

Consider the option A: Since the plants have mutations and they cannot develop fertile embryos and are induced to fruit by artificial hormone treatment. therefore the fruits will be seed less.

Consider the option B: since the plants are triploid, hence can not form normal gametes. However there is the parthenocarpic gene which induces parthenocarpy and hence seedless fruits will be produced.

Consider the option C: Since the plants are self incompatible and possess parthenocarpic gene, hence parthenocarpy will produce seedless fruits.

Consider the option D: This is simple grafting wherein a scion from one plant is grafted to a stock of other plant. In this case there will be normal fruit set with seed production.

Thank you