a) P(Ezra is accepted into all five of these programs) = 0.15 x 0.12 x 0.19 x 0.24 x 0.31
= 0.00025
b) P(she is accepted into none of these programs) = (1 - 0.15) x (1 - 0.12) x (1 - 0.19) x (1 - 0.24) x (1 - 0.31)
= 0.85 x 0.88 x 0.81 x 0.76 x 0.69
= 0.31772
c) P(She is accepted only in Carnegie Mellon) = (1 - 0.15) x (1 - 0.12) x 0.19 x (1 - 0.24) x (1 - 0.31)
= 0.07453
d) It is possible for her to get accepted by multiple programs.Thus, the distribution here is not mutually exclusive and collectively exclusive. Therefore this doesn't satisfy the conditions for MECE distribution.
help number 1 1. Ezra is entering her senior year of college and would like to...
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