Question

A uniformly charged spherical shell has inner and outer radii of 29.0 cm and 32.0 cm, respectively. A point charge of -45.0 nC is located at the center of the spherical shell. A proton orbits around this arrangement just outside the spherical shell with a speed of 8.39 x 105 m/s. What is the volume charge density of the spherical shell? (Include the sign of the value in your answer.) -6.2E-12 What force supplies the needed centripetal force that keeps the proton in a circular orbit? How is the net charge related to the charge on the spherical shell? uC/m3 Supporting Materials Physical Constants

Answer 1

AP AV= 8.39 x 10 m/s 8=29cm R= 32cm Q=-4500 45x10% Let Electric field at p be e, (CD+9) apply gauss law to of final f, a a2 unG E. una = (a +9) 5 E = Che force on proton = F = XE = et (F= exe) This force supply centripetal force. eXE = mv ex 1 (1+2) = mv for proton to be just outside the shell, a=R ex1 6+2) - my² UTG R Q+q = mvxR - (1.6781027) x (8.39 810) x 0.32 e xq X101 T. 681019x9x109 d+ 2 = 2.6 123X107c 8 + 9 = 0.0261x105 = 261023X15 16 = 261.23 nc q=(261. 23+45) nc = 306.23 no) charge density = a lume - 366.238161 - 8729.46 3 p] - [ 0.32 - 04) Charge clensity = 8.73 x 10 c/m3 Charge density = 8.73 40 /m². Electric force supplies the centripetal force. X169

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