Question

A force F is pulling a 16.0 kg box along a 30 Degree  ramp at a constant velocity. Note that the force F is acting along the ramp surface. Kinetic fictional coefficient of ramp surface is 0.57. Calculate the work done by force F to move the box 8.0 m along that surface? (Hint: Find F first). g=10 m/s^2

Answer 1

Since it is with constant velocity accelration would be 0.

N=mgcos $\theta$ and F= $\mu$ Nsin $\theta$

so F= $\mu$ mg cos $\theta$ sin $\theta$

Work done by force = F*d = $\mu$ mg cos $\theta$ sin $\theta$ *d

putting in values we get Work done = .57 *16*10*(1.732/4)* 8=315.92 J