An oil (SG = 0.9) Issues from the pipe shown in the figure below at Q = 35 ft/h. The length of the pipe is 5 ft. The kinetic energy correction factor a ls 2.0. 10 ft References eBook & Resources Section Break Difficulty: Medium value: 20.00 polnts What is the kinematic viscosity of the oil in ft/s? Round the answer to six decimal places. The kinematic viscosity of the oil is ft/s.
Water flow steady through a pipe with Dia= 0.75 m at point 1 and Dia= 1.5 m at point 2 as shown below. Find the velocity and the volume flow rate at the exit point.( Xwater = 9800 N/m3) D = 1.5 m D = 0.75 m (1) water in (2) V D = 2 m im . 7m. SG=0.88 T 0.5 m 0.3 in 0.2m 0-5 m 0.5m SG=13.5S SG:13.55
Water flow steady through a pipe with Dia= 0.75 m at point 1 and Dia= 1.5 m at point 2 as shown below. Find the velocity and the volume flow rate at the exit point.( xwater = 9800 N/m3) D = 1.5 m D = 0.75 m (1) BS water in (2) D = 2 m im o 7m. SG=0.88 T 0.3 in 0.5 m 0.2 in 0.5m SG=13.5S SG:13.55
Water flow steady through a pipe with Dia=0.75 m at point 1 and Dia= 1.5 m at point 2 as shown below. Find the velocity and the volume flow rate at the exit point.(Ywater = 9800 N/m) D-1.5 m D=0.75 m (1) water (2) Y D = 2 m 1m 0.7m SG=0.88 T 0.3m 0.5m 02 m 0.5m 0.5m S6=13.5S SG:13.55
1.16 An inverted U-tube manometer containing oil (SG = 0.8) is connected to two vessels as shown in Fig. 1.16. The vessel on the left contains liquid carbon tetrachloride (density 1600 kg/m3), is closed and pressurised to 50 kPa (gauge). The vessel on the right contains water and is open to the atmosphere. Use the given data to determine the depth H of the liquid stored in the left vessel. Ans: 0.89 m Carbon tetrachloride 50 kPa 02 m Oil...
6 The venture meter shown in Figure below carries oil (sg 0.90). The specific gravity of the gage fluid in the manometer is 1.40. a. Find the pressure difference between points A and B h. Find the velocity at pointA c. Calculate the volume flow rate of oil. 8 Marks [8 Marks 17 Marks] 75-mm How A. 200- nside 0.50 m
Find the pressure at the center of pipe A. (S = p water ) Oil (S - 0.8) Water T90 cm 150 cm Water Mercury (S = 13.6) 130 cm 30 cm
find pressuare at A
2 m Pipe 00 mm Water Mercury (sg = 13.54) FIGURE 3.26 Problem 3.62.
Water flows through a pipe reducer as shown in the figure. If the manometer reading h - 2 m. Find the flow rate in Liters per second. Assume DI-15 cm, D2-10 cm. SG:-0.80 a. What is the effect of the angle θ b. Is this a practical arrangement, if yes why, if not how would you improve it? c. Ca n mercury be used as a manometer fluid in this arrangement? Why, or why not? SG D2 Water Di
Water...
(1 point) Sa SG 3 SG 2 13 3 SG 2 By UBC Engineering Given the following fluid properties and dimensions SG1 0.725 SG2 1.225 SG3-1.725 SG4 2.225 h- 0.48 m h10.28 m h2 0.68 m h3 -1.08 m Find the gauge pressure at B if the gauge pressure at A is PA - 165 Pa gauge