Question

Week 4, Question 2: Use the force method to determine the force in each member of the truss. Take a = 7 kN, b = 8 kN, c = 11 kN and EA = 20000 kN (for all the members). B) 2 m 3 m— 3 m Please fill in your solutions here: a) FAB = -11 kN Your last answer was interpreted as follows: -11 b) FAC = 0 KN Your last answer was interpreted as follows: 0 c) FBC = 7.21 kN Your last answer was interpreted as follows: 7.21 d) FBD = -6 kN
part a, b, c & d are correct

Answer 1

• Statical element or indetene maaj +3 - 10-2x6+3 - 13-12 IV No.of in Detmery = 1 Remove member DE Ra AL RARE = 7+3+1 = 26 KH-0 EMA=0 8x3 + 11x6 - REX 6=0 RE= 15km2 RA= 1KN [Rx=0 Joint I FAB FAB=RAJ Scanned with CamScanner FAB= 11kN compreesia

(Facto] TKN FOD tomos 3 dlm inė 371w 57 Efy=0 7+11-FBc sing =D foca e fbc= 4513 = 2513 KN teresting FBD = Foc coso = 2513x3 1 / 1 FBD = 6kN compression Joint D Foo to for ffed Foe= 8KH compressi FBD = For=6kN compresory Joint ® a fer-Foe sino-fersino fcf fer = 18-2513x2) los Scanned with hamiland CamScanner 2513 E/791/

ref= 2513 KN tensim Efn=0 FBc Coso - FCE + FefCOSO O IFCE=0 Joint E 4 FEF Fef=\SKN compressin 15 DE Now and applied Remore unit all load in centered meuben load که سالها RA Efy RAIRE=0 EMA=0 I - 1asinox b + 1 cosox2 sino x3 - REX6=0 2eoso-sino Scanned with CamScanner i

[RE =o) [Ran=0 RA=o S - Joint a KAB=0 Kaczo - - - Joint I D Kof Icoso = KDF > Koop compressin Joint a keo= kefsino tef= 2 2 2 St Kef= Les tension kee = kef Cose = HET compresin a companie Scanned with CamScanner

Joint KEF= 1 KCE = 1/2 KCE Scanned with CamScanner

BC 7. Member Force (P Unit Force(Kg AB T-110 ACO 0 BD -6 O 7.2111 CD -8 -0.5547002 CE 0 -0.83205029 | 7.2111 DF -0.83205029 EF | -15 -0.5547002 DE O -5 Length (P*K*L) K^2*L 2 T0 0 3 0 0 3 + 0 0 3.60555128 2 8.8752 0.61538 -5 3 0 2.07692 4. 3.60555128 26 3.60555 1.9 14.9769 2.07692 -1 16.641 0.61538 -1 3.60555128 0 3.60555 - Sum 66.493 12.596 CF 3 CS CamScanner Scanner

2- - PleL AE - 66.4931 12.5957 3 k2L AE 1x=-51279025 Force - x in all member TE=p+kx FAB=-11 KN I FBC= I T-BC= 7.2111 KN 7.2111 KN I Fed=-5077KN 1 1 fef= fer 193208 kN I For= -1.6076kN ECE = 4039241kN FER- 12072kt Scafing with 6 KN CamScanner EDE= -5.279KM
​​​​​​